Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
PhoenixFire
Group Title
A free electron in an oscillating field experiences a force \(\mathbf{F}=e\mathbf {E}(t)\), where \(\mathbf {E}(t)=\mathbf {E_0}sin(wt)\) and \(\mathbf {E_0}=(E_0,0,0)\) < completely in the x direction.
if x(t) is the xcoordinate of the electron and we assume \(x(0)=\frac{dx}{dt}(0)=0\)
How do we find the equation of motion along the 'x' axis from this information?
 4 months ago
 4 months ago
PhoenixFire Group Title
A free electron in an oscillating field experiences a force \(\mathbf{F}=e\mathbf {E}(t)\), where \(\mathbf {E}(t)=\mathbf {E_0}sin(wt)\) and \(\mathbf {E_0}=(E_0,0,0)\) < completely in the x direction. if x(t) is the xcoordinate of the electron and we assume \(x(0)=\frac{dx}{dt}(0)=0\) How do we find the equation of motion along the 'x' axis from this information?
 4 months ago
 4 months ago

This Question is Closed

Mashy Group TitleBest ResponseYou've already chosen the best response.2
\[m \frac{d^2x}{dt^2} + eE_oSin(\omega t) = 0\] solve this differential equatinon :D
 4 months ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.0
@Mashy how did you come up with that differential?
 4 months ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.0
\(F=ma=eE(t)\) \(m\frac{d^2 x}{dt^2}=eE(t)\) Is this what you did?
 4 months ago

Mashy Group TitleBest ResponseYou've already chosen the best response.2
yes yes.. sorry.. i was in a hurry and so i forgot to mention :D
 4 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.