Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
valiyuh
Group Title
Can someone please explain to me how calculate the ph of 0.003 M HCLplease?
 4 months ago
 4 months ago
valiyuh Group Title
Can someone please explain to me how calculate the ph of 0.003 M HCLplease?
 4 months ago
 4 months ago

This Question is Open

Kainui Group TitleBest ResponseYou've already chosen the best response.3
\[pH=  \log_{10}([H^+])\] The pH is just the negative logarithm of the Hydrogen ion concentration. It's purely out of convenience since it's easier to talk about the pH rather than the really small number usually is. So what is concentration? It's literally just the number of hydrogen atoms per volume of liquid. We count them by using moles rather than just the direct number. But if you have say, 6 mols of Hydrogen you can just multiply that by 6.02x10^23 to get the actual number of atoms just like if you have 6 dozen eggs you can multiply that by 12 to get the actual number of eggs. Since you're given 0.003 M HCl that's a good sign, you don't have to calculate anything! M is the symbol for Molar which is just moles per Liter \[1 Molar = 1 \frac{moles}{Liter}\] Or written like this, same thing.\[1 M = 1 \frac{mol}{L}\] Since HCl is a Strong Acid it will dissociate completely, giving you 1 mol of H+ for every mol of HCl you have. Another strong acid such as H2SO4 will dissociate 2 mols of H+ for every mol of acid you have, so you would multiply by 2 in that case. So that being said, we really just plug the number in, and out comes our pH! \[pH=\log_{10}(.003)\]
 4 months ago

valiyuh Group TitleBest ResponseYou've already chosen the best response.1
Thank you so much !
 4 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.