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Ash90

  • 8 months ago

i need help solving this replace r and g with the following and find the time-out. r=91-7* sqrt(t) g=14*t

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  1. Ash90
    • 8 months ago
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    @AkashdeepDeb

  2. Ash90
    • 8 months ago
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    idk what to do with this?

  3. AkashdeepDeb
    • 8 months ago
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    Do we just have to find the time in this question? And is any other equation given? :)

  4. Ash90
    • 8 months ago
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    yes we just need to find the time in this equation but I have to write it out by showing my work. let me check and see if anything else is given...

  5. Ash90
    • 8 months ago
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    that's all nothing else is need right now.

  6. Ash90
    • 8 months ago
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    what this is is a programm that when you do the calculations the colors are set up to do what you need them to.

  7. AkashdeepDeb
    • 8 months ago
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    That's cool! Well, if you have to find the value of t in terms of r or in terms of g, you can do that. But if you want to find the value of t, in terms of real numbers, [Although, I don't think it is possible] I suggest you tag someone else. The equations you have posted are called Parametric equations, you can also express r in terms of g here but I am not sure how to go about calculating the sole value of 't'. :)

  8. Ash90
    • 8 months ago
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    could i show you what i have and maybe you can help from there?

  9. Ash90
    • 8 months ago
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    |dw:1397796459525:dw|

  10. Ash90
    • 8 months ago
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    |dw:1397796552699:dw|

  11. AkashdeepDeb
    • 8 months ago
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    Yes, I can help you from there! But is it given that r=g ? Because you have equated it over there! :D

  12. Ash90
    • 8 months ago
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    well i think what i had to do was set them equal to each other if i'm not mistaking i think thats what the teacher wanted.

  13. AkashdeepDeb
    • 8 months ago
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    Okay. So if r=g \(91-7 \sqrt{t} = 14t\) \(91-14t = 7\sqrt{t}\) \(Squaring ~~both ~~sides ~~we~~ get:\) \((91-14t)^2 = 49t\) \(196t^2 + 8281 - 2548t = 49t\) \(196t^2 - 2597t + 8281\) \(~~~~~~~~~~~~Where~~[a = 196, ~b = -2597,~c = 8281]\) Use the quadratic equation below to solve for \(t\): \[\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] Got it? :)

  14. Ash90
    • 8 months ago
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    \[t=\frac{ 53+\sqrt{105} }{ 8 }, t=\frac{ 53-\sqrt{105} }{ 8 }\]

  15. AkashdeepDeb
    • 8 months ago
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    Yes, if you got that by calculating the above equation, then yes. :)

  16. Ash90
    • 8 months ago
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    yay!

  17. Ash90
    • 8 months ago
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    can we do one more?

  18. AkashdeepDeb
    • 8 months ago
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    Sure!

  19. Ash90
    • 8 months ago
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    okay thanks.

  20. Ash90
    • 8 months ago
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    \[r=7*t^2-51*t+92\]

  21. Ash90
    • 8 months ago
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    for this one i thought using quadratic formula right of hand would be a good idea

  22. AkashdeepDeb
    • 8 months ago
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    You cannot always do that. The quadratic formula can only be used when f(x) = ax^2 + bx + c = 0 [And zero only] As it gives us the zeroes of the polynomial/expression. What you could do is write it like this: 7t^2 - 51t + 92 - r = 0 Now apply the quadratic formula, considering, [c = 92-r] Getting this? :) You may also try this by the completing-the-square method, although I am not a 100% sure if it'll work here.

  23. Ash90
    • 8 months ago
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    |dw:1397798167883:dw|

  24. Ash90
    • 8 months ago
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    |dw:1397798377673:dw|

  25. Ash90
    • 8 months ago
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    thanks for the help

  26. AkashdeepDeb
    • 8 months ago
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    :)

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