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yeah_i_suck_at_math
Group Title
If (x + 5)^2 = 35, what is the approximate positive value of x?
0.92
2.65
3.16
5.48
 7 months ago
 7 months ago
yeah_i_suck_at_math Group Title
If (x + 5)^2 = 35, what is the approximate positive value of x? 0.92 2.65 3.16 5.48
 7 months ago
 7 months ago

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yeah_i_suck_at_math Group TitleBest ResponseYou've already chosen the best response.0
my answer is A
 7 months ago

BillBell Group TitleBest ResponseYou've already chosen the best response.0
\[x + 5 = +/ \sqrt{35}\] Question asks for the positve value of x. So we have \[x = 5 + \sqrt{35}\] because \[x = 5  \sqrt{35}\] is negative. You can use a calculator or google to get the approximate value of this.
 7 months ago

kym02 Group TitleBest ResponseYou've already chosen the best response.0
I got A too but i'm not sure
 7 months ago

BillBell Group TitleBest ResponseYou've already chosen the best response.0
That's what I get too.
 7 months ago

yeah_i_suck_at_math Group TitleBest ResponseYou've already chosen the best response.0
yeah its A, thanks guys, can you help me on another question, its harder than this one
 7 months ago

yeah_i_suck_at_math Group TitleBest ResponseYou've already chosen the best response.0
Debbie sells cookies and hotdogs. The daily cost of making cookies is $460 more than the difference between the square of the number of cookies sold and 20 times the number of cookies sold. The daily cost of making hotdogs is modeled by the following equation: C(x) = 2x2  80x + 1,200 C(x) is the cost in dollars of selling x hotdogs. Which statement best compares the minimum daily cost of making cookies and hotdogs? It is greater for hotdogs than cookies because the approximate minimum cost is $300 for cookies and $392 for hotdogs. It is greater for hotdogs than cookies because the approximate minimum cost is $360 for cookies and $400 for hotdogs. It is greater for cookies than hotdogs because the approximate minimum cost is $400 for cookies and $360 for hotdogs. It is greater for cookies than hotdogs because the approximate minimum cost is $392 for cookies and $300 for hotdogs.
 7 months ago

yeah_i_suck_at_math Group TitleBest ResponseYou've already chosen the best response.0
my answer is C
 7 months ago

yeah_i_suck_at_math Group TitleBest ResponseYou've already chosen the best response.0
or B, not sure though
 7 months ago

BillBell Group TitleBest ResponseYou've already chosen the best response.0
dC(x)/dx = 2x  20 = 0 => x = 10 => minimum cost of cookies = 460 + 10^2  20(10) = 360 dH(x)/dx = 4x  80 = 0 => x = 20 => minimum cost of hotdogs = 1200 + 2(20^2)  80(20) = 400
 7 months ago

yeah_i_suck_at_math Group TitleBest ResponseYou've already chosen the best response.0
so it was B
 7 months ago

BillBell Group TitleBest ResponseYou've already chosen the best response.0
So it appears.
 7 months ago

yeah_i_suck_at_math Group TitleBest ResponseYou've already chosen the best response.0
ok and last one .. A quadratic equation is shown below: x2  8x + 13 = 0 Which of the following is the first correct step to write the above equation in the form (x  p)2 = q, where p and q are integers? Subtract 5 from both sides of the equation Subtract 3 from both sides of the equation Add 5 to both sides of the equation < my answer Add 3 to both sides of the equation
 7 months ago

BillBell Group TitleBest ResponseYou've already chosen the best response.0
Back in a few minutes ...
 7 months ago

BillBell Group TitleBest ResponseYou've already chosen the best response.0
\[( x  p)^{2} = x^{2}  2p + p ^{2}\] Compare the equation you have been given with this one. Then 2p = 8 and therefore p =4. With this value of p we get \[x^{2}  8x + 16\] and we want to make the original equation into this so we subtract 3 from both sides.
 7 months ago

yeah_i_suck_at_math Group TitleBest ResponseYou've already chosen the best response.0
yeah i already finished this question but thanks
 7 months ago

yeah_i_suck_at_math Group TitleBest ResponseYou've already chosen the best response.0
will you help me on a new question please ? @BillBell
 7 months ago
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