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Gabylovesyou

  • 8 months ago

FInd the perimeter of the image

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  1. Gabylovesyou
    • 8 months ago
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    37 units 38 units 39 units 40 units

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  2. Gabylovesyou
    • 8 months ago
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    @ash2326 @phi

  3. ganeshie8
    • 8 months ago
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    to find the perimeter of given shape, you need to find out sides first

  4. ganeshie8
    • 8 months ago
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    perimeter = sum of all sides

  5. ganeshie8
    • 8 months ago
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    know how to find the length of sides on coordinate plane ?

  6. Gabylovesyou
    • 8 months ago
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    distance formula ?

  7. ganeshie8
    • 8 months ago
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    yes, but for that u need to figure out coordinates of points and plug them in the formula... which is a pain... and u need to do it for 5 times... since u have 5 sides

  8. ganeshie8
    • 8 months ago
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    there is a simpler way to do this, which uses the distance formula in disguise...

  9. Gabylovesyou
    • 8 months ago
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    ok..

  10. Gabylovesyou
    • 8 months ago
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    whats the simpler way ?

  11. ganeshie8
    • 8 months ago
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  12. ganeshie8
    • 8 months ago
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    use pythagorean theorem : that red side = \(\sqrt{2^2+6^2} = \sqrt{40}\)

  13. ganeshie8
    • 8 months ago
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    this is exact same as distance formula, but this is felt simple because, you're not plugging in the coordinates... instead you're just counting the number of grids...

  14. ganeshie8
    • 8 months ago
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    use whichever u feel is easy...

  15. Gabylovesyou
    • 8 months ago
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    how did u solve that ^ ... like how did u get 40 ?

  16. ganeshie8
    • 8 months ago
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    the goal is to find the length of all sides and add up

  17. Gabylovesyou
    • 8 months ago
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    ok..

  18. ganeshie8
    • 8 months ago
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    did u get how I got : red side = \(\sqrt{2^2+6^2} \)

  19. ganeshie8
    • 8 months ago
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    ?

  20. Gabylovesyou
    • 8 months ago
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    i know how u got the 2 and the 6... just not the 40 ...

  21. ganeshie8
    • 8 months ago
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    oh cool :) ive just skipped a step : red side = \(\sqrt{2^2+6^2} = \sqrt{4+36} = ?\)

  22. Gabylovesyou
    • 8 months ago
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    ohhh ok

  23. ganeshie8
    • 8 months ago
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    find the lengths of remaining sides in any way u wish, and add them all up

  24. Gabylovesyou
    • 8 months ago
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    for pt it would be 4^2 + 10^2

  25. Gabylovesyou
    • 8 months ago
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    which is 116

  26. ganeshie8
    • 8 months ago
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    Yes ! dont forget the sqrt

  27. Gabylovesyou
    • 8 months ago
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    ok...

  28. ganeshie8
    • 8 months ago
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    \(PT^2 = 4^2 + 10^2\) \(PT = \sqrt{4^2 + 10^2} = \sqrt{116}\)

  29. Gabylovesyou
    • 8 months ago
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    TS is 7

  30. Gabylovesyou
    • 8 months ago
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    how do i do SR O.o

  31. ganeshie8
    • 8 months ago
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  32. Gabylovesyou
    • 8 months ago
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    50 ok..

  33. ganeshie8
    • 8 months ago
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    *sqrt...

  34. Gabylovesyou
    • 8 months ago
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    right... lol and then the last side is sqrt 61 ?

  35. Gabylovesyou
    • 8 months ago
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    do i add them all ?

  36. ganeshie8
    • 8 months ago
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    yup ! perimeter = length around a shape = sum of all sides

  37. Gabylovesyou
    • 8 months ago
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    sqrt 274

  38. Gabylovesyou
    • 8 months ago
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    ?

  39. ganeshie8
    • 8 months ago
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    lol no

  40. ganeshie8
    • 8 months ago
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    you cannot add radicals like that

  41. ganeshie8
    • 8 months ago
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    \(\large \sqrt{a} + \sqrt{b} + \sqrt{c} ~ \ne ~ \sqrt{a + b+ c}\)

  42. Gabylovesyou
    • 8 months ago
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    hm i got 60 ;/

  43. ganeshie8
    • 8 months ago
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    You got : \(QP = \sqrt{40}\) \(PT = \sqrt{116}\) \(TS = 7\) \(SR = \sqrt{50}\) \(RQ = \sqrt{61}\)

  44. ganeshie8
    • 8 months ago
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    right ?

  45. Gabylovesyou
    • 8 months ago
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    yes

  46. ganeshie8
    • 8 months ago
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    plug each sqrt in ur calcualtor and add them all

  47. ganeshie8
    • 8 months ago
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    \(QP = \sqrt{40} = \color{red}{6.32}\) \(PT = \sqrt{116} = \color{red}{10.77}\) \(TS = 7 = \color{red}{7}\) \(SR = \sqrt{50} = \color{red}{7.07}\) \(RQ = \sqrt{61} = \color{red}{7.81}\) --------------------------------------- perimeter = \(\color{Red}{?}\)

  48. Gabylovesyou
    • 8 months ago
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    38. 97

  49. ganeshie8
    • 8 months ago
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    wolfram says the same : http://www.wolframalpha.com/input/?i=sqrt%2840%29+%2B+sqrt%28116%29+%2B+7+%2B+sqrt%2850%29+%2B+sqrt%2861%29

  50. Gabylovesyou
    • 8 months ago
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    so should i put 39 ?

  51. Gabylovesyou
    • 8 months ago
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    or try it the long way to double check

  52. ganeshie8
    • 8 months ago
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    rounding it becomes : \(38.97 \approx 39\)

  53. ganeshie8
    • 8 months ago
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    Nope, both are one and same... you may try for practice if u want maybe :)

  54. Gabylovesyou
    • 8 months ago
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    okay :) thank you!

  55. ganeshie8
    • 8 months ago
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    np :)

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