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Gabylovesyou Group Title

FInd the perimeter of the image

  • 6 months ago
  • 6 months ago

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  1. Gabylovesyou Group Title
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    37 units 38 units 39 units 40 units

    • 6 months ago
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  2. Gabylovesyou Group Title
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    @ash2326 @phi

    • 6 months ago
  3. ganeshie8 Group Title
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    to find the perimeter of given shape, you need to find out sides first

    • 6 months ago
  4. ganeshie8 Group Title
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    perimeter = sum of all sides

    • 6 months ago
  5. ganeshie8 Group Title
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    know how to find the length of sides on coordinate plane ?

    • 6 months ago
  6. Gabylovesyou Group Title
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    distance formula ?

    • 6 months ago
  7. ganeshie8 Group Title
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    yes, but for that u need to figure out coordinates of points and plug them in the formula... which is a pain... and u need to do it for 5 times... since u have 5 sides

    • 6 months ago
  8. ganeshie8 Group Title
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    there is a simpler way to do this, which uses the distance formula in disguise...

    • 6 months ago
  9. Gabylovesyou Group Title
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    ok..

    • 6 months ago
  10. Gabylovesyou Group Title
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    whats the simpler way ?

    • 6 months ago
  11. ganeshie8 Group Title
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    • 6 months ago
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  12. ganeshie8 Group Title
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    use pythagorean theorem : that red side = \(\sqrt{2^2+6^2} = \sqrt{40}\)

    • 6 months ago
  13. ganeshie8 Group Title
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    this is exact same as distance formula, but this is felt simple because, you're not plugging in the coordinates... instead you're just counting the number of grids...

    • 6 months ago
  14. ganeshie8 Group Title
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    use whichever u feel is easy...

    • 6 months ago
  15. Gabylovesyou Group Title
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    how did u solve that ^ ... like how did u get 40 ?

    • 6 months ago
  16. ganeshie8 Group Title
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    the goal is to find the length of all sides and add up

    • 6 months ago
  17. Gabylovesyou Group Title
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    ok..

    • 6 months ago
  18. ganeshie8 Group Title
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    did u get how I got : red side = \(\sqrt{2^2+6^2} \)

    • 6 months ago
  19. ganeshie8 Group Title
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    ?

    • 6 months ago
  20. Gabylovesyou Group Title
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    i know how u got the 2 and the 6... just not the 40 ...

    • 6 months ago
  21. ganeshie8 Group Title
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    oh cool :) ive just skipped a step : red side = \(\sqrt{2^2+6^2} = \sqrt{4+36} = ?\)

    • 6 months ago
  22. Gabylovesyou Group Title
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    ohhh ok

    • 6 months ago
  23. ganeshie8 Group Title
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    find the lengths of remaining sides in any way u wish, and add them all up

    • 6 months ago
  24. Gabylovesyou Group Title
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    for pt it would be 4^2 + 10^2

    • 6 months ago
  25. Gabylovesyou Group Title
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    which is 116

    • 6 months ago
  26. ganeshie8 Group Title
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    Yes ! dont forget the sqrt

    • 6 months ago
  27. Gabylovesyou Group Title
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    ok...

    • 6 months ago
  28. ganeshie8 Group Title
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    \(PT^2 = 4^2 + 10^2\) \(PT = \sqrt{4^2 + 10^2} = \sqrt{116}\)

    • 6 months ago
  29. Gabylovesyou Group Title
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    TS is 7

    • 6 months ago
  30. Gabylovesyou Group Title
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    how do i do SR O.o

    • 6 months ago
  31. ganeshie8 Group Title
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    • 6 months ago
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  32. Gabylovesyou Group Title
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    50 ok..

    • 6 months ago
  33. ganeshie8 Group Title
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    *sqrt...

    • 6 months ago
  34. Gabylovesyou Group Title
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    right... lol and then the last side is sqrt 61 ?

    • 6 months ago
  35. Gabylovesyou Group Title
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    do i add them all ?

    • 6 months ago
  36. ganeshie8 Group Title
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    yup ! perimeter = length around a shape = sum of all sides

    • 6 months ago
  37. Gabylovesyou Group Title
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    sqrt 274

    • 6 months ago
  38. Gabylovesyou Group Title
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    ?

    • 6 months ago
  39. ganeshie8 Group Title
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    lol no

    • 6 months ago
  40. ganeshie8 Group Title
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    you cannot add radicals like that

    • 6 months ago
  41. ganeshie8 Group Title
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    \(\large \sqrt{a} + \sqrt{b} + \sqrt{c} ~ \ne ~ \sqrt{a + b+ c}\)

    • 6 months ago
  42. Gabylovesyou Group Title
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    hm i got 60 ;/

    • 6 months ago
  43. ganeshie8 Group Title
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    You got : \(QP = \sqrt{40}\) \(PT = \sqrt{116}\) \(TS = 7\) \(SR = \sqrt{50}\) \(RQ = \sqrt{61}\)

    • 6 months ago
  44. ganeshie8 Group Title
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    right ?

    • 6 months ago
  45. Gabylovesyou Group Title
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    yes

    • 6 months ago
  46. ganeshie8 Group Title
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    plug each sqrt in ur calcualtor and add them all

    • 6 months ago
  47. ganeshie8 Group Title
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    \(QP = \sqrt{40} = \color{red}{6.32}\) \(PT = \sqrt{116} = \color{red}{10.77}\) \(TS = 7 = \color{red}{7}\) \(SR = \sqrt{50} = \color{red}{7.07}\) \(RQ = \sqrt{61} = \color{red}{7.81}\) --------------------------------------- perimeter = \(\color{Red}{?}\)

    • 6 months ago
  48. Gabylovesyou Group Title
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    38. 97

    • 6 months ago
  49. ganeshie8 Group Title
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    wolfram says the same : http://www.wolframalpha.com/input/?i=sqrt%2840%29+%2B+sqrt%28116%29+%2B+7+%2B+sqrt%2850%29+%2B+sqrt%2861%29

    • 6 months ago
  50. Gabylovesyou Group Title
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    so should i put 39 ?

    • 6 months ago
  51. Gabylovesyou Group Title
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    or try it the long way to double check

    • 6 months ago
  52. ganeshie8 Group Title
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    rounding it becomes : \(38.97 \approx 39\)

    • 6 months ago
  53. ganeshie8 Group Title
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    Nope, both are one and same... you may try for practice if u want maybe :)

    • 6 months ago
  54. Gabylovesyou Group Title
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    okay :) thank you!

    • 6 months ago
  55. ganeshie8 Group Title
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    np :)

    • 6 months ago
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