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Fanduekisses
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**PRECALC HELP PLEASE How to verify the identity tan(x+pi/2)=cotx ?
 6 months ago
 6 months ago
Fanduekisses Group Title
**PRECALC HELP PLEASE How to verify the identity tan(x+pi/2)=cotx ?
 6 months ago
 6 months ago

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Fanduekisses Group TitleBest ResponseYou've already chosen the best response.0
Do I USE the cofunction identity?
 6 months ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
You use whatever works. Let's see what happens when you use the cofunction identity.
 6 months ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
tan(x+y) = (tan x +tan y) / (1 tan x tan y)
 6 months ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
here y is pi/2
 6 months ago

Fanduekisses Group TitleBest ResponseYou've already chosen the best response.0
ooooh I see so x is x and y is pi/2?
 6 months ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
yes
 6 months ago

Fanduekisses Group TitleBest ResponseYou've already chosen the best response.0
so x + pi/2/ 1x + pi/2 ?
 6 months ago

Fanduekisses Group TitleBest ResponseYou've already chosen the best response.0
is that correct?
 6 months ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
no
 6 months ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
tan x + tan 90/ (1 tan90 *tanx)
 6 months ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
then divide numerator and denominator by tan 90 . as u know tan 90 is "infinite" and 1 / "infinte" = 0 Now try to solve it
 6 months ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
no
 6 months ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
(tan x/tan 90+1 ) / [(1 /tan 90)  tanx)]
 6 months ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
got it ?
 6 months ago
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