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kelly234

  • 8 months ago

Can someone PLEASE help me out?! medal AND fan!!

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  1. kelly234
    • 8 months ago
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  2. Muhammad_Nauman_Umair
    • 8 months ago
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    so [-30 -5 ] [-20 - 4 ] [+20 +30] + [-12 -32 ] [-35 +35] [ 24 +32 ]

  3. kelly234
    • 8 months ago
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    woah wait.. how in the world did you get that?

  4. Muhammad_Nauman_Umair
    • 8 months ago
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    now we have to add these two matrices to get the answer

  5. kelly234
    • 8 months ago
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    oook.. i think i see how you got that now.. you multiplied everything in the first matrix by - 5 right?

  6. Muhammad_Nauman_Umair
    • 8 months ago
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    ok simply multiply the elements of matrix A with -5 and B with +4 we get the above rresult

  7. kelly234
    • 8 months ago
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    ooh ook.. and now just add them to get the answer?:)

  8. Muhammad_Nauman_Umair
    • 8 months ago
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    yes

  9. kelly234
    • 8 months ago
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    ok hold on...

  10. Muhammad_Nauman_Umair
    • 8 months ago
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    ok

  11. kelly234
    • 8 months ago
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    -50 -9 8 -2 59 67

  12. kelly234
    • 8 months ago
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    right?

  13. kelly234
    • 8 months ago
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    but thats not an option.. these r the options i have:

  14. Muhammad_Nauman_Umair
    • 8 months ago
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    [-50 -9] [8 - 2 ] [-11 +67]

  15. Muhammad_Nauman_Umair
    • 8 months ago
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    simply your addition was wrong

  16. kelly234
    • 8 months ago
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    ooooh i forgot the negative sign on the last one.. ok.. Thanks so much!!:) can you help me with more please?:)

  17. kelly234
    • 8 months ago
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  18. Muhammad_Nauman_Umair
    • 8 months ago
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    ok i m waiting for the next one

  19. kelly234
    • 8 months ago
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    i posted it :)

  20. Muhammad_Nauman_Umair
    • 8 months ago
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    now multiply 2 with the matrix

  21. Muhammad_Nauman_Umair
    • 8 months ago
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    take the result on the other side

  22. Muhammad_Nauman_Umair
    • 8 months ago
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    after solving the subtraction of two matrices we get a matrix which will be divided by 2 and hence X will b found

  23. kelly234
    • 8 months ago
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    ok.. i got 4 -16 -8 4 for the first part..

  24. Muhammad_Nauman_Umair
    • 8 months ago
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    yes

  25. kelly234
    • 8 months ago
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    now what?

  26. Muhammad_Nauman_Umair
    • 8 months ago
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    take this matrix on the other side

  27. kelly234
    • 8 months ago
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    what does that mean? like i add it with the other one?

  28. Muhammad_Nauman_Umair
    • 8 months ago
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    if u have the case like X +Y =Z what u do is to find X X= Z-Y

  29. kelly234
    • 8 months ago
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    oh so subtract the 1st one with the 2nd one?

  30. Muhammad_Nauman_Umair
    • 8 months ago
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    yes

  31. kelly234
    • 8 months ago
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    ok i got 0 -22 -10 12 is that right?

  32. kelly234
    • 8 months ago
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    no.. its not an option..:/

  33. Muhammad_Nauman_Umair
    • 8 months ago
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    no

  34. kelly234
    • 8 months ago
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    what did i do wrong?

  35. Muhammad_Nauman_Umair
    • 8 months ago
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    here y is the matrix u got by multiplying by 2 and the matrix on the right side is Z so u have to do Z-Y

  36. kelly234
    • 8 months ago
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    could you please show me how?

  37. Muhammad_Nauman_Umair
    • 8 months ago
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    [4 -6] - [4 -16] [2 -8] [-8 4]

  38. kelly234
    • 8 months ago
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    i got 0 -22 10 -12 but thats not an option either.

  39. Muhammad_Nauman_Umair
    • 8 months ago
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    0 10 10 -12

  40. kelly234
    • 8 months ago
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    thats still not an option?

  41. Muhammad_Nauman_Umair
    • 8 months ago
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    u again made mistake in addition and subtraction

  42. kelly234
    • 8 months ago
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    the one you posted wasnt an option either..

  43. Muhammad_Nauman_Umair
    • 8 months ago
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    this wholle thing is 2X now u have to divide it by two to get the answer

  44. Muhammad_Nauman_Umair
    • 8 months ago
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    got it or not?

  45. kelly234
    • 8 months ago
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    i guess so.. heres another one

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  46. Muhammad_Nauman_Umair
    • 8 months ago
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    the third one was the answer

  47. kelly234
    • 8 months ago
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    r u sure? can you tell me how you figured it out?

  48. Muhammad_Nauman_Umair
    • 8 months ago
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    answer for the last question was the third option do u still have problem in the last question ? problem 2

  49. kelly234
    • 8 months ago
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    yea i got that, thanks:) i need help on the next question that i posted:)

  50. Muhammad_Nauman_Umair
    • 8 months ago
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    ok

  51. Muhammad_Nauman_Umair
    • 8 months ago
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    do u know how to multiply a matrices

  52. kelly234
    • 8 months ago
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    yep

  53. Muhammad_Nauman_Umair
    • 8 months ago
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    then here we go

  54. Muhammad_Nauman_Umair
    • 8 months ago
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    In question matrix is given [TD=6 FG=3 S=2 PAT=1] this is of order 1*4

  55. Muhammad_Nauman_Umair
    • 8 months ago
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    for team A [TD=3 FG=2 S=1 PAT=0] when we write it in horizontal way like the above one we don't fulfill the condition of multiplication i.e no. of colums of 1st matrix = no. of rows of 2nd matrix so we have to write in this way [ TD=3 ] [ FG=2 ] [ S=1 ] [ PAT=0 ] of order 4*1 by multiplying this vector with the above one we will get what is required

  56. Muhammad_Nauman_Umair
    • 8 months ago
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    [6 3 2 1] * [ 3 ] [ 2 ] [ 1 ] [ 0 ]

  57. Muhammad_Nauman_Umair
    • 8 months ago
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    now multiply them and get the answer for team A

  58. kelly234
    • 8 months ago
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    i got 36..

  59. kelly234
    • 8 months ago
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    and thats an option!! thanks so much!!:)

  60. Muhammad_Nauman_Umair
    • 8 months ago
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    no no no its 26

  61. Muhammad_Nauman_Umair
    • 8 months ago
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    [18+ 6+2 +0] = 26

  62. kelly234
    • 8 months ago
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    ooh.. well that's still an option.. thanks!!:)

  63. Muhammad_Nauman_Umair
    • 8 months ago
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    now did u get the method to solve it ?

  64. Muhammad_Nauman_Umair
    • 8 months ago
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    i never tried so hard to make someone learn something . Now i can go sleep with ease..

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