kelly234
Can someone PLEASE help me out?! medal AND fan!!
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kelly234
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Muhammad_Nauman_Umair
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so
[-30 -5 ] [-20 - 4 ]
[+20 +30] + [-12 -32 ]
[-35 +35] [ 24 +32 ]
kelly234
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woah wait.. how in the world did you get that?
Muhammad_Nauman_Umair
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now we have to add these two matrices to get the answer
kelly234
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oook.. i think i see how you got that now.. you multiplied everything in the first matrix by - 5 right?
Muhammad_Nauman_Umair
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ok simply multiply the elements of matrix A with -5
and B with +4 we get the above rresult
kelly234
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ooh ook.. and now just add them to get the answer?:)
kelly234
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ok hold on...
kelly234
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-50 -9
8 -2
59 67
kelly234
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right?
kelly234
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but thats not an option.. these r the options i have:
Muhammad_Nauman_Umair
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[-50 -9]
[8 - 2 ]
[-11 +67]
Muhammad_Nauman_Umair
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simply your addition was wrong
kelly234
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ooooh i forgot the negative sign on the last one.. ok.. Thanks so much!!:) can you help me with more please?:)
kelly234
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Muhammad_Nauman_Umair
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ok i m waiting for the next one
kelly234
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i posted it :)
Muhammad_Nauman_Umair
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now multiply 2 with the matrix
Muhammad_Nauman_Umair
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take the result on the other side
Muhammad_Nauman_Umair
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after solving the subtraction of two matrices we get a matrix which will be divided by 2
and hence X will b found
kelly234
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ok.. i got
4 -16
-8 4
for the first part..
kelly234
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now what?
Muhammad_Nauman_Umair
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take this matrix on the other side
kelly234
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what does that mean? like i add it with the other one?
Muhammad_Nauman_Umair
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if u have the case like
X +Y =Z
what u do is to find X
X= Z-Y
kelly234
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oh so subtract the 1st one with the 2nd one?
kelly234
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ok i got
0 -22
-10 12
is that right?
kelly234
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no.. its not an option..:/
kelly234
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what did i do wrong?
Muhammad_Nauman_Umair
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here y is the matrix u got by multiplying by 2
and the matrix on the right side is Z
so u have to do Z-Y
kelly234
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could you please show me how?
Muhammad_Nauman_Umair
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[4 -6] - [4 -16]
[2 -8] [-8 4]
kelly234
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i got
0 -22
10 -12
but thats not an option either.
kelly234
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thats still not an option?
Muhammad_Nauman_Umair
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u again made mistake in addition and subtraction
kelly234
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the one you posted wasnt an option either..
Muhammad_Nauman_Umair
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this wholle thing is 2X
now u have to divide it by two to get the answer
kelly234
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i guess so.. heres another one
Muhammad_Nauman_Umair
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the third one was the answer
kelly234
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r u sure? can you tell me how you figured it out?
Muhammad_Nauman_Umair
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answer for the last question was the third option
do u still have problem in the last question ? problem 2
kelly234
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yea i got that, thanks:) i need help on the next question that i posted:)
Muhammad_Nauman_Umair
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do u know how to multiply a matrices
kelly234
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yep
Muhammad_Nauman_Umair
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In question matrix is given
[TD=6 FG=3 S=2 PAT=1] this is of order 1*4
Muhammad_Nauman_Umair
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for team A
[TD=3 FG=2 S=1 PAT=0]
when we write it in horizontal way like the above one we don't fulfill the condition of multiplication i.e no. of colums of 1st matrix = no. of rows of 2nd matrix
so we have to write in this way
[ TD=3 ]
[ FG=2 ]
[ S=1 ]
[ PAT=0 ] of order 4*1
by multiplying this vector with the above one we will get what is required
Muhammad_Nauman_Umair
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[6 3 2 1] * [ 3 ]
[ 2 ]
[ 1 ]
[ 0 ]
Muhammad_Nauman_Umair
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now multiply them and get the answer for team A
kelly234
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i got 36..
kelly234
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and thats an option!! thanks so much!!:)
kelly234
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ooh.. well that's still an option.. thanks!!:)
Muhammad_Nauman_Umair
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now did u get the method to solve it ?
Muhammad_Nauman_Umair
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i never tried so hard to make someone learn something .
Now i can go sleep with ease..