1. kelly234

so [-30 -5 ] [-20 - 4 ] [+20 +30] + [-12 -32 ] [-35 +35] [ 24 +32 ]

3. kelly234

woah wait.. how in the world did you get that?

now we have to add these two matrices to get the answer

5. kelly234

oook.. i think i see how you got that now.. you multiplied everything in the first matrix by - 5 right?

ok simply multiply the elements of matrix A with -5 and B with +4 we get the above rresult

7. kelly234

yes

9. kelly234

ok hold on...

ok

11. kelly234

-50 -9 8 -2 59 67

12. kelly234

right?

13. kelly234

but thats not an option.. these r the options i have:

[-50 -9] [8 - 2 ] [-11 +67]

16. kelly234

ooooh i forgot the negative sign on the last one.. ok.. Thanks so much!!:) can you help me with more please?:)

17. kelly234

ok i m waiting for the next one

19. kelly234

i posted it :)

now multiply 2 with the matrix

take the result on the other side

after solving the subtraction of two matrices we get a matrix which will be divided by 2 and hence X will b found

23. kelly234

ok.. i got 4 -16 -8 4 for the first part..

yes

25. kelly234

now what?

take this matrix on the other side

27. kelly234

what does that mean? like i add it with the other one?

if u have the case like X +Y =Z what u do is to find X X= Z-Y

29. kelly234

oh so subtract the 1st one with the 2nd one?

yes

31. kelly234

ok i got 0 -22 -10 12 is that right?

32. kelly234

no.. its not an option..:/

no

34. kelly234

what did i do wrong?

here y is the matrix u got by multiplying by 2 and the matrix on the right side is Z so u have to do Z-Y

36. kelly234

could you please show me how?

[4 -6] - [4 -16] [2 -8] [-8 4]

38. kelly234

i got 0 -22 10 -12 but thats not an option either.

0 10 10 -12

40. kelly234

thats still not an option?

42. kelly234

the one you posted wasnt an option either..

this wholle thing is 2X now u have to divide it by two to get the answer

got it or not?

45. kelly234

i guess so.. heres another one

the third one was the answer

47. kelly234

r u sure? can you tell me how you figured it out?

answer for the last question was the third option do u still have problem in the last question ? problem 2

49. kelly234

yea i got that, thanks:) i need help on the next question that i posted:)

ok

do u know how to multiply a matrices

52. kelly234

yep

then here we go

In question matrix is given [TD=6 FG=3 S=2 PAT=1] this is of order 1*4

for team A [TD=3 FG=2 S=1 PAT=0] when we write it in horizontal way like the above one we don't fulfill the condition of multiplication i.e no. of colums of 1st matrix = no. of rows of 2nd matrix so we have to write in this way [ TD=3 ] [ FG=2 ] [ S=1 ] [ PAT=0 ] of order 4*1 by multiplying this vector with the above one we will get what is required

[6 3 2 1] * [ 3 ] [ 2 ] [ 1 ] [ 0 ]

now multiply them and get the answer for team A

58. kelly234

i got 36..

59. kelly234

and thats an option!! thanks so much!!:)

no no no its 26

[18+ 6+2 +0] = 26

62. kelly234

ooh.. well that's still an option.. thanks!!:)

now did u get the method to solve it ?