Can someone PLEASE help me out?! medal AND fan!!

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Can someone PLEASE help me out?! medal AND fan!!

Mathematics
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1 Attachment
so [-30 -5 ] [-20 - 4 ] [+20 +30] + [-12 -32 ] [-35 +35] [ 24 +32 ]
woah wait.. how in the world did you get that?

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now we have to add these two matrices to get the answer
oook.. i think i see how you got that now.. you multiplied everything in the first matrix by - 5 right?
ok simply multiply the elements of matrix A with -5 and B with +4 we get the above rresult
ooh ook.. and now just add them to get the answer?:)
yes
ok hold on...
ok
-50 -9 8 -2 59 67
right?
but thats not an option.. these r the options i have:
[-50 -9] [8 - 2 ] [-11 +67]
simply your addition was wrong
ooooh i forgot the negative sign on the last one.. ok.. Thanks so much!!:) can you help me with more please?:)
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ok i m waiting for the next one
i posted it :)
now multiply 2 with the matrix
take the result on the other side
after solving the subtraction of two matrices we get a matrix which will be divided by 2 and hence X will b found
ok.. i got 4 -16 -8 4 for the first part..
yes
now what?
take this matrix on the other side
what does that mean? like i add it with the other one?
if u have the case like X +Y =Z what u do is to find X X= Z-Y
oh so subtract the 1st one with the 2nd one?
yes
ok i got 0 -22 -10 12 is that right?
no.. its not an option..:/
no
what did i do wrong?
here y is the matrix u got by multiplying by 2 and the matrix on the right side is Z so u have to do Z-Y
could you please show me how?
[4 -6] - [4 -16] [2 -8] [-8 4]
i got 0 -22 10 -12 but thats not an option either.
0 10 10 -12
thats still not an option?
u again made mistake in addition and subtraction
the one you posted wasnt an option either..
this wholle thing is 2X now u have to divide it by two to get the answer
got it or not?
i guess so.. heres another one
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the third one was the answer
r u sure? can you tell me how you figured it out?
answer for the last question was the third option do u still have problem in the last question ? problem 2
yea i got that, thanks:) i need help on the next question that i posted:)
ok
do u know how to multiply a matrices
yep
then here we go
In question matrix is given [TD=6 FG=3 S=2 PAT=1] this is of order 1*4
for team A [TD=3 FG=2 S=1 PAT=0] when we write it in horizontal way like the above one we don't fulfill the condition of multiplication i.e no. of colums of 1st matrix = no. of rows of 2nd matrix so we have to write in this way [ TD=3 ] [ FG=2 ] [ S=1 ] [ PAT=0 ] of order 4*1 by multiplying this vector with the above one we will get what is required
[6 3 2 1] * [ 3 ] [ 2 ] [ 1 ] [ 0 ]
now multiply them and get the answer for team A
i got 36..
and thats an option!! thanks so much!!:)
no no no its 26
[18+ 6+2 +0] = 26
ooh.. well that's still an option.. thanks!!:)
now did u get the method to solve it ?
i never tried so hard to make someone learn something . Now i can go sleep with ease..

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