anonymous
  • anonymous
Can someone PLEASE help me out?! medal AND fan!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
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Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
so [-30 -5 ] [-20 - 4 ] [+20 +30] + [-12 -32 ] [-35 +35] [ 24 +32 ]
anonymous
  • anonymous
woah wait.. how in the world did you get that?

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Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
now we have to add these two matrices to get the answer
anonymous
  • anonymous
oook.. i think i see how you got that now.. you multiplied everything in the first matrix by - 5 right?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
ok simply multiply the elements of matrix A with -5 and B with +4 we get the above rresult
anonymous
  • anonymous
ooh ook.. and now just add them to get the answer?:)
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
yes
anonymous
  • anonymous
ok hold on...
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
ok
anonymous
  • anonymous
-50 -9 8 -2 59 67
anonymous
  • anonymous
right?
anonymous
  • anonymous
but thats not an option.. these r the options i have:
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
[-50 -9] [8 - 2 ] [-11 +67]
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
simply your addition was wrong
anonymous
  • anonymous
ooooh i forgot the negative sign on the last one.. ok.. Thanks so much!!:) can you help me with more please?:)
anonymous
  • anonymous
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Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
ok i m waiting for the next one
anonymous
  • anonymous
i posted it :)
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
now multiply 2 with the matrix
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
take the result on the other side
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
after solving the subtraction of two matrices we get a matrix which will be divided by 2 and hence X will b found
anonymous
  • anonymous
ok.. i got 4 -16 -8 4 for the first part..
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
yes
anonymous
  • anonymous
now what?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
take this matrix on the other side
anonymous
  • anonymous
what does that mean? like i add it with the other one?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
if u have the case like X +Y =Z what u do is to find X X= Z-Y
anonymous
  • anonymous
oh so subtract the 1st one with the 2nd one?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
yes
anonymous
  • anonymous
ok i got 0 -22 -10 12 is that right?
anonymous
  • anonymous
no.. its not an option..:/
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
no
anonymous
  • anonymous
what did i do wrong?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
here y is the matrix u got by multiplying by 2 and the matrix on the right side is Z so u have to do Z-Y
anonymous
  • anonymous
could you please show me how?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
[4 -6] - [4 -16] [2 -8] [-8 4]
anonymous
  • anonymous
i got 0 -22 10 -12 but thats not an option either.
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
0 10 10 -12
anonymous
  • anonymous
thats still not an option?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
u again made mistake in addition and subtraction
anonymous
  • anonymous
the one you posted wasnt an option either..
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
this wholle thing is 2X now u have to divide it by two to get the answer
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
got it or not?
anonymous
  • anonymous
i guess so.. heres another one
1 Attachment
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
the third one was the answer
anonymous
  • anonymous
r u sure? can you tell me how you figured it out?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
answer for the last question was the third option do u still have problem in the last question ? problem 2
anonymous
  • anonymous
yea i got that, thanks:) i need help on the next question that i posted:)
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
ok
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
do u know how to multiply a matrices
anonymous
  • anonymous
yep
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
then here we go
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
In question matrix is given [TD=6 FG=3 S=2 PAT=1] this is of order 1*4
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
for team A [TD=3 FG=2 S=1 PAT=0] when we write it in horizontal way like the above one we don't fulfill the condition of multiplication i.e no. of colums of 1st matrix = no. of rows of 2nd matrix so we have to write in this way [ TD=3 ] [ FG=2 ] [ S=1 ] [ PAT=0 ] of order 4*1 by multiplying this vector with the above one we will get what is required
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
[6 3 2 1] * [ 3 ] [ 2 ] [ 1 ] [ 0 ]
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
now multiply them and get the answer for team A
anonymous
  • anonymous
i got 36..
anonymous
  • anonymous
and thats an option!! thanks so much!!:)
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
no no no its 26
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
[18+ 6+2 +0] = 26
anonymous
  • anonymous
ooh.. well that's still an option.. thanks!!:)
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
now did u get the method to solve it ?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
i never tried so hard to make someone learn something . Now i can go sleep with ease..

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