Given the equation of damped shm \[\frac{d^2x}{dt^2} +B\frac{dx}{dt}+Cx=0\]
And the solution \[x=Ae^{-\frac{t}{T}} cos(wt+d)\]
Where T is the time it takes for the amplitude to fall a factor of 1/e.
How do I find T in terms of B and C?

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Yeah, I guess you wouldn't solve that...

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