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theEric
 9 months ago
Best ResponseYou've already chosen the best response.1This is an issue where we can use the definition of acceleration. That is, the change in velocity per some change in time. Also, acceleration is gravitational acceleration. \(a=\dfrac{\Delta v}{\Delta t}\) And \(g=a\), right? So \(g=\dfrac{\Delta v}{\Delta t}\) So, we have that the initial velocity is 0 at the start of the fall. So, you can think that the change in velocity is the new velocity. If you want to see the math that agrees, \(\Delta v=v_fv_0=v_f0=v_f\) Does that help?
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