mari69755
verify equation identity
(1cot^2)/(1+cot^2)+1=2 sin^2



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mari69755
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I try solving it and it was not an identity but I am not sure I am right.

tgawade
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dw:1398203236677:dw

mari69755
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yeah i I did that but at the end of it I did not get the 2sin^2

tgawade
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dw:1398203617892:dw

mari69755
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yes

tgawade
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At the end use property sin^2 + cos^2 = 1

tgawade
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at denominator

mari69755
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yeah that would give me 1/sin^2

tgawade
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Please check it

mari69755
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wait would my denominator be (sin^2+cos^2)/ sin^2?

tgawade
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dw:1398204432505:dw

mari69755
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dw:1398204540377:dw

tgawade
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similarly at denominatior , so sin^2 get cancel from both numerator & denominator ..

mari69755
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oh wow. so there would only be left cos^2 right

tgawade
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dw:1398204881696:dw

tgawade
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Okay
?

mari69755
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yeah i understand that

tgawade
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what would be the next step ?

tgawade
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lcd

tgawade
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Are you there ?

mari69755
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use the denominator equal one

tgawade
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dw:1398205488285:dw

tgawade
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So what do you get ?

mari69755
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at the top part do you multiply the a times y?

tgawade
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in our step x = (sin^2  cos^ ) & y = sin^2 + cos^2 & a = 1

mari69755
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yes so it would be sin^2cos^2+(sin^2cos^2) all divided by sin^2+cos^2?

mari69755
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okay I understood it never mine. Thank you so much for your help. I did get 2sin^2 at the end.

tgawade
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You are welcome :)