anonymous
  • anonymous
verify equation identity (1-cot^2)/(1+cot^2)+1=2 sin^2
Trigonometry
schrodinger
  • schrodinger
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anonymous
  • anonymous
I try solving it and it was not an identity but I am not sure I am right.
anonymous
  • anonymous
|dw:1398203236677:dw|
anonymous
  • anonymous
yeah i I did that but at the end of it I did not get the 2sin^2

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anonymous
  • anonymous
|dw:1398203617892:dw|
anonymous
  • anonymous
yes
anonymous
  • anonymous
At the end use property sin^2 + cos^2 = 1
anonymous
  • anonymous
at denominator
anonymous
  • anonymous
yeah that would give me 1/sin^2
anonymous
  • anonymous
Please check it
anonymous
  • anonymous
wait would my denominator be (sin^2+cos^2)/ sin^2?
anonymous
  • anonymous
|dw:1398204432505:dw|
anonymous
  • anonymous
|dw:1398204540377:dw|
anonymous
  • anonymous
similarly at denominatior , so sin^2 get cancel from both numerator & denominator ..
anonymous
  • anonymous
oh wow. so there would only be left -cos^2 right
anonymous
  • anonymous
|dw:1398204881696:dw|
anonymous
  • anonymous
Okay ?
anonymous
  • anonymous
yeah i understand that
anonymous
  • anonymous
what would be the next step ?
anonymous
  • anonymous
lcd
anonymous
  • anonymous
Are you there ?
anonymous
  • anonymous
use the denominator equal one
anonymous
  • anonymous
|dw:1398205488285:dw|
anonymous
  • anonymous
So what do you get ?
anonymous
  • anonymous
at the top part do you multiply the a times y?
anonymous
  • anonymous
in our step x = (sin^2 - cos^ ) & y = sin^2 + cos^2 & a = 1
anonymous
  • anonymous
yes so it would be sin^2-cos^2+(sin^2-cos^2) all divided by sin^2+cos^2?
anonymous
  • anonymous
okay I understood it never mine. Thank you so much for your help. I did get 2sin^2 at the end.
anonymous
  • anonymous
You are welcome :)

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