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mari69755

  • one year ago

verify equation identity (1-cot^2)/(1+cot^2)+1=2 sin^2

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  1. mari69755
    • one year ago
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    I try solving it and it was not an identity but I am not sure I am right.

  2. tgawade
    • one year ago
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    |dw:1398203236677:dw|

  3. mari69755
    • one year ago
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    yeah i I did that but at the end of it I did not get the 2sin^2

  4. tgawade
    • one year ago
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    |dw:1398203617892:dw|

  5. mari69755
    • one year ago
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    yes

  6. tgawade
    • one year ago
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    At the end use property sin^2 + cos^2 = 1

  7. tgawade
    • one year ago
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    at denominator

  8. mari69755
    • one year ago
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    yeah that would give me 1/sin^2

  9. tgawade
    • one year ago
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    Please check it

  10. mari69755
    • one year ago
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    wait would my denominator be (sin^2+cos^2)/ sin^2?

  11. tgawade
    • one year ago
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    |dw:1398204432505:dw|

  12. mari69755
    • one year ago
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    |dw:1398204540377:dw|

  13. tgawade
    • one year ago
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    similarly at denominatior , so sin^2 get cancel from both numerator & denominator ..

  14. mari69755
    • one year ago
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    oh wow. so there would only be left -cos^2 right

  15. tgawade
    • one year ago
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    |dw:1398204881696:dw|

  16. tgawade
    • one year ago
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    Okay ?

  17. mari69755
    • one year ago
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    yeah i understand that

  18. tgawade
    • one year ago
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    what would be the next step ?

  19. tgawade
    • one year ago
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    lcd

  20. tgawade
    • one year ago
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    Are you there ?

  21. mari69755
    • one year ago
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    use the denominator equal one

  22. tgawade
    • one year ago
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    |dw:1398205488285:dw|

  23. tgawade
    • one year ago
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    So what do you get ?

  24. mari69755
    • one year ago
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    at the top part do you multiply the a times y?

  25. tgawade
    • one year ago
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    in our step x = (sin^2 - cos^ ) & y = sin^2 + cos^2 & a = 1

  26. mari69755
    • one year ago
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    yes so it would be sin^2-cos^2+(sin^2-cos^2) all divided by sin^2+cos^2?

  27. mari69755
    • one year ago
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    okay I understood it never mine. Thank you so much for your help. I did get 2sin^2 at the end.

  28. tgawade
    • one year ago
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    You are welcome :)

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