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verify equation identity (1-cot^2)/(1+cot^2)+1=2 sin^2

Trigonometry
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I try solving it and it was not an identity but I am not sure I am right.
|dw:1398203236677:dw|
yeah i I did that but at the end of it I did not get the 2sin^2

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Other answers:

|dw:1398203617892:dw|
yes
At the end use property sin^2 + cos^2 = 1
at denominator
yeah that would give me 1/sin^2
Please check it
wait would my denominator be (sin^2+cos^2)/ sin^2?
|dw:1398204432505:dw|
|dw:1398204540377:dw|
similarly at denominatior , so sin^2 get cancel from both numerator & denominator ..
oh wow. so there would only be left -cos^2 right
|dw:1398204881696:dw|
Okay ?
yeah i understand that
what would be the next step ?
lcd
Are you there ?
use the denominator equal one
|dw:1398205488285:dw|
So what do you get ?
at the top part do you multiply the a times y?
in our step x = (sin^2 - cos^ ) & y = sin^2 + cos^2 & a = 1
yes so it would be sin^2-cos^2+(sin^2-cos^2) all divided by sin^2+cos^2?
okay I understood it never mine. Thank you so much for your help. I did get 2sin^2 at the end.
You are welcome :)

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