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ElleCullen

  • 2 years ago

sin(a - b) = sina cosb + cosa sinb for all values of a and b. True or false?

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  1. student_basil
    • 2 years ago
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    false, because the rules for sine a+b identities are. \[\sin(a +b) = \sin(a) ~\cos(b) + \cos(a) ~\sin(b)\]\[\sin(a -b) = \sin(a) ~\cos(b) - \cos(a) ~\sin(b)\]

  2. student_basil
    • 2 years ago
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    you have two of them mixed, and two sides are for sure not always equal.

  3. ElleCullen
    • 2 years ago
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    Thank you :)

  4. student_basil
    • 2 years ago
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    \(\normalsize\color{black}{ \bf You}\) \(\normalsize\color{black}{ \bf welcome~!}\)

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