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## ElleCullen 2 years ago sin(a - b) = sina cosb + cosa sinb for all values of a and b. True or false?

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1. anonymous

false, because the rules for sine a+b identities are. $\sin(a +b) = \sin(a) ~\cos(b) + \cos(a) ~\sin(b)$$\sin(a -b) = \sin(a) ~\cos(b) - \cos(a) ~\sin(b)$

2. anonymous

you have two of them mixed, and two sides are for sure not always equal.

3. ElleCullen

Thank you :)

4. anonymous

$$\normalsize\color{black}{ \bf You}$$ $$\normalsize\color{black}{ \bf welcome~!}$$

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