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anonymous

  • 2 years ago

why is it easier to 'hit' a nucleus with a neutron than with a proton?

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  1. theEric
    • 2 years ago
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    I really don't know. But if I had to guess, I'd think about the charge. What do you think?

  2. theEric
    • 2 years ago
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    Think about the nucleus, the neutron, and proton.

  3. anonymous
    • 2 years ago
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    I was thinking the same thing...ehh i dont know :l

  4. theEric
    • 2 years ago
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    Well, copy and paste this, and list their charges: Neutron: Proton: Nucleus:

  5. anonymous
    • 2 years ago
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    Neutron: neutral Proton: +1 Nucleus: +1

  6. theEric
    • 2 years ago
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    Right! And that's good enough. Really, the nucleus will have a +1 charge for each proton, so the total charge is +1\(\times\) the number of protons. So, you know the like charges repel, right?

  7. anonymous
    • 2 years ago
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    yep

  8. theEric
    • 2 years ago
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    Right! So, you have this.|dw:1398301781038:dw| Which will be easier to move, and why?

  9. theEric
    • 2 years ago
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    If you need a hint, think about the repelling. That electrostatic force.

  10. anonymous
    • 2 years ago
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    oh so since the protons and nucleus are positively charged, repulsion will thus occur making it difficult to hit the nucleus. And since the neutron is neutral, it won't have any effect. Infact, it would actually be attracted to the nucleus. Am I right?

  11. anonymous
    • 2 years ago
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    oh wait, scratch that attracted part 'cause opposite attracts.

  12. theEric
    • 2 years ago
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    With your edit, you're completely correct! :) I think you covered it all!

  13. anonymous
    • 2 years ago
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    That was quite simple :)

  14. theEric
    • 2 years ago
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    After you broke it down, yep! :)

  15. anonymous
    • 2 years ago
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    Thanks for your help!

  16. theEric
    • 2 years ago
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    That's what a lot of problems take. They're complex when you think of everything together. But it's easier when you understand it, which sometimes breaking down pieces so you can understand them and put the pieces back together. Then the problem will be easier.

  17. anonymous
    • 2 years ago
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    hmm yeah indeed!

  18. theEric
    • 2 years ago
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    Your welcome! :) Take care!

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