Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

DrPepperx3

  • 8 months ago

help? 2 questions medal c:!

  • This Question is Closed
  1. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1.A 2000 W toaster operates on a household circuit of 200 V. What is the resistance of the wire the make up the heating element of the toaster?

  2. ksaimouli
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Resistance = Voltage / Current

  3. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    0.1?

  4. ksaimouli
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Si unit of current is amp but they gave us power

  5. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    electric power (watts)=votlage*amperage, amperage=voltage/resistance so 2000W=200V*Amperage (10amp). 10amp=200V/resistance (20)

  6. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    20 ohms

  7. ksaimouli
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[power=\frac{ V }{ I }\]

  8. ksaimouli
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    solve for V

  9. ksaimouli
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    from above equation

  10. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ty :) @ksaimouli and @SalvadorV kk hold on

  11. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you have the intensity formula wrong

  12. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    me?

  13. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sorry the power formula

  14. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    P=V*I

  15. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh so I got it wrong?

  16. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, Watts=Volts*Amps Amps=Volts/Ohms

  17. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh wait im confused .-. sorry

  18. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    watts=volts^2/ohms 2000=200^2/ohms ohms=200^2/2000 = 40 000/2000=20 ohms

  19. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    don't worry, we all make mistakes

  20. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I feel stupid :l but what is ohms?

  21. ksaimouli
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    resistance (unit)

  22. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ohms is the measure for resistance

  23. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oohh ok! ty for helping me c: do you mind helping with 1 more?

  24. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    and ksaimouli has his formula wrong .-.

  25. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sure

  26. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that's why I got confused :c and kk

  27. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2.An electronic device is rated at 0.35 W when connected to 150 V. What is the resistance of this device?

  28. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    see, its the same kind of question so \[0.35W=150V*amps\]

  29. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so \[amps=\frac{ 0.35W }{ 150V }\]

  30. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I was just about to put that lol

  31. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ty again :)

  32. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    and we know that \[Amps=\frac{ volts }{ ohms }, 0.00233333333=\frac{ 150V }{ Ohms }\]

  33. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    remember ohms are the unit for resistance, normally noted with the sign\[\Omega \]

  34. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    here we have to substitute for ohms, so we pass them to the left side multiplying, and then we pass the 0.00233333333 dividing the voltage

  35. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so we get \[\Omega=\frac{ 150V }{ 0.00233333333Amp }\]

  36. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    got it ! :) so =64285.72

  37. Jagking
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea.

  38. Jagking
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry they left u so soon.

  39. DrPepperx3
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    um ok

  40. Jagking
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wow. nice pic.

  41. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    perfect! :D

  42. Jagking
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wow dude. ur late.

  43. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    .-. ok, whatever you say

  44. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I'm actually trying to help people here instead of flirting you know?

  45. Jagking
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i'm helping finish the work u left unfinished. plus i could get her before u do anyway.

  46. SalvadorV
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I don't care about that, I have a girlfriend, plus just hopping in and saying "yes" is not exactly helping much

  47. Jagking
    • 8 months ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i know. but i also know not 2 leave a girl hanging.

  48. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.