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first, what shape does the graph make?

The graph makes a parabola when completed

@FibonacciChick666, what do you mean it can't be graphed?

'graphed' I mean, it's a number line as stated

Continuing what Turtlemuffin was saying, you have
x^2 - 1 = 0 which factors to (x + 1)(x - 1) = 0

My question is, after you have your two x-intercepts, how do you find the vertex from (x+1)(x-1)=0?

We can use the vertex formula to graph the vertex.
\(x = -\dfrac{b}{2a}\)

In this case b = 0 and a = 1, so
\[x = -\frac{0}{2(1)} = 0\]

@Hero , one variable= 1-D , no?

So, the graph would look like this?

ah, now that I re-read the prompt, I understand.

It wanted the roots, by looking at the related graph