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kylewendt
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How do you graph the quadratic equation 3x^2=3?
I need help, my EOC is next Tuesday.
 3 months ago
 3 months ago
kylewendt Group Title
How do you graph the quadratic equation 3x^2=3? I need help, my EOC is next Tuesday.
 3 months ago
 3 months ago

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TurtleMuffin Group TitleBest ResponseYou've already chosen the best response.1
First you can divide both sides by 3 to get x^2 = 1. Subtract 1 from both sides and you have x^2  1 = 0. The roots of this are 1 and 1. So this is a standard parabola shifted down one united passing through 1 and 1 on the xaxis.
 3 months ago

FibonacciChick666 Group TitleBest ResponseYou've already chosen the best response.0
first, what shape does the graph make?
 3 months ago

kylewendt Group TitleBest ResponseYou've already chosen the best response.0
The graph makes a parabola when completed
 3 months ago

FibonacciChick666 Group TitleBest ResponseYou've already chosen the best response.0
good, now, that is an important concept, so now, you have one slight problem, This is only in one variable(x) so you can't graph it. Are you sure you copied the question correctly?
 3 months ago

kylewendt Group TitleBest ResponseYou've already chosen the best response.0
Yes. The exact question is: What are the solutions of the equation 3x^2=3? Use a graph of the related function.
 3 months ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
@FibonacciChick666, what do you mean it can't be graphed?
 3 months ago

FibonacciChick666 Group TitleBest ResponseYou've already chosen the best response.0
'graphed' I mean, it's a number line as stated
 3 months ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
Continuing what Turtlemuffin was saying, you have x^2  1 = 0 which factors to (x + 1)(x  1) = 0
 3 months ago

kylewendt Group TitleBest ResponseYou've already chosen the best response.0
My question is, after you have your two xintercepts, how do you find the vertex from (x+1)(x1)=0?
 3 months ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
We can use the vertex formula to graph the vertex. \(x = \dfrac{b}{2a}\)
 3 months ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
In this case b = 0 and a = 1, so \[x = \frac{0}{2(1)} = 0\]
 3 months ago

FibonacciChick666 Group TitleBest ResponseYou've already chosen the best response.0
@Hero , one variable= 1D , no?
 3 months ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
Since \(x = 0\), we can insert 0 into the expression to get y = \(0^2  1 = 1\) so the vertex is \((0,1)\)
 3 months ago

kylewendt Group TitleBest ResponseYou've already chosen the best response.0
So, the graph would look like this?
 3 months ago

TurtleMuffin Group TitleBest ResponseYou've already chosen the best response.1
That is an algebraic approach. You should know the graph of y=x^2. It's the standard parabola. We simplified your given equation into 0 = x^2  1. The "minus 1" tells us our standard parabola shifts down one unit. Therefore its xcoordinate remains the same, and it's ycoordinate is shifted down 1 unit from 0, i.e. it's now 1. You can remember all the formulas you want, but if you don't see how an algebraic equation is related to its graphical representation, you won't enjoy math too much. That is has how the graph looks like though!
 3 months ago

FibonacciChick666 Group TitleBest ResponseYou've already chosen the best response.0
ah, now that I reread the prompt, I understand.
 3 months ago

FibonacciChick666 Group TitleBest ResponseYou've already chosen the best response.0
It wanted the roots, by looking at the related graph
 3 months ago

kylewendt Group TitleBest ResponseYou've already chosen the best response.0
Thank you all for explaining, as I understand this concept now. My algebra teacher is one of the worst (I know that sounds generic), and intentionally ignores my questions to her on assignments because she doesn't like me. This really helps.
 3 months ago
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