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 10 months ago
How do you graph the quadratic equation 3x^2=3?
I need help, my EOC is next Tuesday.
 10 months ago
How do you graph the quadratic equation 3x^2=3? I need help, my EOC is next Tuesday.

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TurtleMuffin
 10 months ago
Best ResponseYou've already chosen the best response.1First you can divide both sides by 3 to get x^2 = 1. Subtract 1 from both sides and you have x^2  1 = 0. The roots of this are 1 and 1. So this is a standard parabola shifted down one united passing through 1 and 1 on the xaxis.

FibonacciChick666
 10 months ago
Best ResponseYou've already chosen the best response.0first, what shape does the graph make?

kylewendt
 10 months ago
Best ResponseYou've already chosen the best response.0The graph makes a parabola when completed

FibonacciChick666
 10 months ago
Best ResponseYou've already chosen the best response.0good, now, that is an important concept, so now, you have one slight problem, This is only in one variable(x) so you can't graph it. Are you sure you copied the question correctly?

kylewendt
 10 months ago
Best ResponseYou've already chosen the best response.0Yes. The exact question is: What are the solutions of the equation 3x^2=3? Use a graph of the related function.

Hero
 10 months ago
Best ResponseYou've already chosen the best response.0@FibonacciChick666, what do you mean it can't be graphed?

FibonacciChick666
 10 months ago
Best ResponseYou've already chosen the best response.0'graphed' I mean, it's a number line as stated

Hero
 10 months ago
Best ResponseYou've already chosen the best response.0Continuing what Turtlemuffin was saying, you have x^2  1 = 0 which factors to (x + 1)(x  1) = 0

kylewendt
 10 months ago
Best ResponseYou've already chosen the best response.0My question is, after you have your two xintercepts, how do you find the vertex from (x+1)(x1)=0?

Hero
 10 months ago
Best ResponseYou've already chosen the best response.0We can use the vertex formula to graph the vertex. \(x = \dfrac{b}{2a}\)

Hero
 10 months ago
Best ResponseYou've already chosen the best response.0In this case b = 0 and a = 1, so \[x = \frac{0}{2(1)} = 0\]

FibonacciChick666
 10 months ago
Best ResponseYou've already chosen the best response.0@Hero , one variable= 1D , no?

Hero
 10 months ago
Best ResponseYou've already chosen the best response.0Since \(x = 0\), we can insert 0 into the expression to get y = \(0^2  1 = 1\) so the vertex is \((0,1)\)

kylewendt
 10 months ago
Best ResponseYou've already chosen the best response.0So, the graph would look like this?

TurtleMuffin
 10 months ago
Best ResponseYou've already chosen the best response.1That is an algebraic approach. You should know the graph of y=x^2. It's the standard parabola. We simplified your given equation into 0 = x^2  1. The "minus 1" tells us our standard parabola shifts down one unit. Therefore its xcoordinate remains the same, and it's ycoordinate is shifted down 1 unit from 0, i.e. it's now 1. You can remember all the formulas you want, but if you don't see how an algebraic equation is related to its graphical representation, you won't enjoy math too much. That is has how the graph looks like though!

FibonacciChick666
 10 months ago
Best ResponseYou've already chosen the best response.0ah, now that I reread the prompt, I understand.

FibonacciChick666
 10 months ago
Best ResponseYou've already chosen the best response.0It wanted the roots, by looking at the related graph

kylewendt
 10 months ago
Best ResponseYou've already chosen the best response.0Thank you all for explaining, as I understand this concept now. My algebra teacher is one of the worst (I know that sounds generic), and intentionally ignores my questions to her on assignments because she doesn't like me. This really helps.
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