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kylewendt
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What is the graph to 2x^2=8? I know this is a standard parabola, but what do you do with the 8?
 6 months ago
 6 months ago
kylewendt Group Title
What is the graph to 2x^2=8? I know this is a standard parabola, but what do you do with the 8?
 6 months ago
 6 months ago

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dg98 Group TitleBest ResponseYou've already chosen the best response.0
are you sure it's a graph? shouldn't it always be equal to y or f(x)?
 6 months ago

kylewendt Group TitleBest ResponseYou've already chosen the best response.1
Yes, it is a graph. If you need me to, I can copy the exact question (Which isn't much different)
 6 months ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
If we graph y = 2x^2 and y = 8 individually, their intersection is the graph for that equation; That said, 2x^2 is indeed a parabola with a bit of vertical stretch. The 8 is a constant. Consider it as a class of points where the yvalue is 8: (x, 8) We can put any xvalue in and get a point on this line, so the line is just a horizontal line through (0, 8)
 6 months ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
Or alternatively, I think you could bring that 8 over to the left: 2x^2  8 = 0 and draw that graph, which is the same parabola but shifted downwards by 8 units. The intersection at y=0 is the solution set in that case.
 6 months ago

kylewendt Group TitleBest ResponseYou've already chosen the best response.1
So, with 2 solutions, 2 and 2, would this be the graph?
 6 months ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
That parabola seems to be flipped upsidedown, implying it has a negative leading coefficient and positive vertical shift upwards. This parabola given by the equation has to be facing up because its leading term is +2. The whole graph will be shifted down 8 units.
 6 months ago

kylewendt Group TitleBest ResponseYou've already chosen the best response.1
Okay, thank you. I see my problem now!
 6 months ago

AccessDenied Group TitleBest ResponseYou've already chosen the best response.1
Great! I'm glad to help! :)
 6 months ago
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