anonymous
  • anonymous
2. A parallelogram has the vertices (-1, 2), (4, 4), (2, -1) and (-3, -3). Determine what type of parallelogram [10 points]. Find the perimeter and area [20 points].
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
That's what I got...but clearly it's not a parallelogram, so what am I doing wrong, and what do I need to do differently?
anonymous
  • anonymous
@ganeshie8, please help!

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ganeshie8
  • ganeshie8
http://prntscr.com/3eu6hv
ganeshie8
  • ganeshie8
^^thats how it should look. graphing is a very good idea, but u dont need to graph to solve this problem.
anonymous
  • anonymous
Ohhh...duh. Apparently I'm going to be stupid today, brilliant. Thnx for the help! :)
ganeshie8
  • ganeshie8
u figured how to work the problem ?
anonymous
  • anonymous
BTW, someone told me the answer to this problem was 12. Are they right? I got 4.2... √((3) – (0))² + ((0) – (3))² = √3² + -3² = √9 + 9 = √18 ≈ 4.2
anonymous
  • anonymous
yes, I did
ganeshie8
  • ganeshie8
show me ur complete work
anonymous
  • anonymous
For the first problem?
ganeshie8
  • ganeshie8
for both
anonymous
  • anonymous
Ah...ok
ganeshie8
  • ganeshie8
what ever u have so far...
anonymous
  • anonymous
just a mo, then
anonymous
  • anonymous
anonymous
  • anonymous
working on the second question now
ganeshie8
  • ganeshie8
Are you given instructions that u need to work it by graphing ?
anonymous
  • anonymous
Yeah, they taught graphing and the distance formula and whatnot
ganeshie8
  • ganeshie8
no, i mean did the instructions specifically ask u to do this by graphing ?
ganeshie8
  • ganeshie8
cuz, u should NOT use graphing unless the instructions say so
ganeshie8
  • ganeshie8
the common/regular way to work this problem is by finding lengths of sides using `distance formula` and the slopes of sides using `slope formula`
anonymous
  • anonymous
http://static.k12.com/eli/bb/343/-1/0/1_124724_23955/-1/0c7f4350276a46b214395670eae2d3ec752620d8/media/e3eb7b41ab24f0e612428cb2ca67db83e139e1b7/83879.PDF
anonymous
  • anonymous
Those were the directions they gave me
ganeshie8
  • ganeshie8
cool :) then you're right ! they want u work it by graphing
anonymous
  • anonymous
Given that they gave me the graph, I would assume that they want me to solve it by graphing, but I also used the distance formula to find the lengths of the sides
anonymous
  • anonymous
ok :)
ganeshie8
  • ganeshie8
good :) your length of sides, and perimeter are correct. but Area is wrong.
ganeshie8
  • ganeshie8
squaring sides will not give u Area for a rhombus.
anonymous
  • anonymous
ohh..just looked it up A - diagonal x diagonal/2
ganeshie8
  • ganeshie8
Area of rhombus = \(\frac{1}{2} d_1 d_2\)
ganeshie8
  • ganeshie8
yes^
anonymous
  • anonymous
Great, now I have to find the diagonals, lol
ganeshie8
  • ganeshie8
its easy from graph
ganeshie8
  • ganeshie8
horizontal diagonal = 3--3 = 6 vertical diagonal = 3--3 = 6
ganeshie8
  • ganeshie8
So, Area = \(\frac{1}{2} d_1 d_2 = \frac{1}{2} 6*6 = 18\)
ganeshie8
  • ganeshie8
And that makes the given rhombus a SQUARE !
ganeshie8
  • ganeshie8
so the given parallelogram is not just a rhombus, its also a SQUARE !
ganeshie8
  • ganeshie8
for the `type of parallelogram `, you should say that its a `square`
ganeshie8
  • ganeshie8
if that makes any sense..
anonymous
  • anonymous
The parallelogram is a rhombus and a square?
ganeshie8
  • ganeshie8
just say its a SQUARE !
anonymous
  • anonymous
rhomus: all equal sides, two pairs of equal angles square: equal sides, equal angles
anonymous
  • anonymous
oh, ok
anonymous
  • anonymous
Does that change my equation for the area, then?
ganeshie8
  • ganeshie8
all squares are parallelograms all squares are rhombuses all squares are rectangles all squares are quadrilaterals
ganeshie8
  • ganeshie8
a square is many things
ganeshie8
  • ganeshie8
yes it will change ur formula, but the answer will be same
anonymous
  • anonymous
I see that, lol
ganeshie8
  • ganeshie8
let me modify it and give u
anonymous
  • anonymous
it will be?
anonymous
  • anonymous
ok
ganeshie8
  • ganeshie8
here is the corrected stuff for question 1 : http://prntscr.com/3euc4h
anonymous
  • anonymous
anonymous
  • anonymous
how do you find the diagonals inside a rhombus?
ganeshie8
  • ganeshie8
use the distance formula
anonymous
  • anonymous
oh, its the same process, ok, hold on
ganeshie8
  • ganeshie8
ok, i presume u knw what a diagonal is :)
ganeshie8
  • ganeshie8
it just connects the opposite vertices
ganeshie8
  • ganeshie8
|dw:1398867292759:dw|
ganeshie8
  • ganeshie8
|dw:1398867314860:dw|
ganeshie8
  • ganeshie8
^^those two line segments joining opposite vertices are diagonals
anonymous
  • anonymous
anonymous
  • anonymous
Is that correct? I found it odd that I got the same area for #1 and #2...but maybe that's just a coincidence
ganeshie8
  • ganeshie8
diagonals are not equal in rhombus
ganeshie8
  • ganeshie8
so u need to calculate the 2nd diagonal also using distance formula
ganeshie8
  • ganeshie8
and then use the area of rhombus formula : Area = \(\frac{1}{2}d_1 d_2\)
anonymous
  • anonymous
anonymous
  • anonymous
@ganeshie8
ganeshie8
  • ganeshie8
looks good !
anonymous
  • anonymous
thnx! :D

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