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2. A parallelogram has the vertices (-1, 2), (4, 4), (2, -1) and (-3, -3). Determine what type of parallelogram [10 points]. Find the perimeter and area [20 points].

Mathematics
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That's what I got...but clearly it's not a parallelogram, so what am I doing wrong, and what do I need to do differently?
@ganeshie8, please help!

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Other answers:

http://prntscr.com/3eu6hv
^^thats how it should look. graphing is a very good idea, but u dont need to graph to solve this problem.
Ohhh...duh. Apparently I'm going to be stupid today, brilliant. Thnx for the help! :)
u figured how to work the problem ?
BTW, someone told me the answer to this problem was 12. Are they right? I got 4.2... √((3) – (0))² + ((0) – (3))² = √3² + -3² = √9 + 9 = √18 ≈ 4.2
yes, I did
show me ur complete work
For the first problem?
for both
Ah...ok
what ever u have so far...
just a mo, then
working on the second question now
Are you given instructions that u need to work it by graphing ?
Yeah, they taught graphing and the distance formula and whatnot
no, i mean did the instructions specifically ask u to do this by graphing ?
cuz, u should NOT use graphing unless the instructions say so
the common/regular way to work this problem is by finding lengths of sides using `distance formula` and the slopes of sides using `slope formula`
http://static.k12.com/eli/bb/343/-1/0/1_124724_23955/-1/0c7f4350276a46b214395670eae2d3ec752620d8/media/e3eb7b41ab24f0e612428cb2ca67db83e139e1b7/83879.PDF
Those were the directions they gave me
cool :) then you're right ! they want u work it by graphing
Given that they gave me the graph, I would assume that they want me to solve it by graphing, but I also used the distance formula to find the lengths of the sides
ok :)
good :) your length of sides, and perimeter are correct. but Area is wrong.
squaring sides will not give u Area for a rhombus.
ohh..just looked it up A - diagonal x diagonal/2
Area of rhombus = \(\frac{1}{2} d_1 d_2\)
yes^
Great, now I have to find the diagonals, lol
its easy from graph
horizontal diagonal = 3--3 = 6 vertical diagonal = 3--3 = 6
So, Area = \(\frac{1}{2} d_1 d_2 = \frac{1}{2} 6*6 = 18\)
And that makes the given rhombus a SQUARE !
so the given parallelogram is not just a rhombus, its also a SQUARE !
for the `type of parallelogram `, you should say that its a `square`
if that makes any sense..
The parallelogram is a rhombus and a square?
just say its a SQUARE !
rhomus: all equal sides, two pairs of equal angles square: equal sides, equal angles
oh, ok
Does that change my equation for the area, then?
all squares are parallelograms all squares are rhombuses all squares are rectangles all squares are quadrilaterals
a square is many things
yes it will change ur formula, but the answer will be same
I see that, lol
let me modify it and give u
it will be?
ok
here is the corrected stuff for question 1 : http://prntscr.com/3euc4h
how do you find the diagonals inside a rhombus?
use the distance formula
oh, its the same process, ok, hold on
ok, i presume u knw what a diagonal is :)
it just connects the opposite vertices
|dw:1398867292759:dw|
|dw:1398867314860:dw|
^^those two line segments joining opposite vertices are diagonals
Is that correct? I found it odd that I got the same area for #1 and #2...but maybe that's just a coincidence
diagonals are not equal in rhombus
so u need to calculate the 2nd diagonal also using distance formula
and then use the area of rhombus formula : Area = \(\frac{1}{2}d_1 d_2\)
looks good !
thnx! :D

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