vera_ewing
  • vera_ewing
The equation of a circle is (x - 8)^2 + (y - 5)^2 = 81. Where is (5, 1) located in relation to the circle? A. In the exterior of the circle B. At the center of the circle C. On the circle D. In the interior of the circle
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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myininaya
  • myininaya
plug the point into (x-8)^2+(y-5)^2
vera_ewing
  • vera_ewing
@myininaya ok i got (5-8)^2+(1-5)^2
myininaya
  • myininaya
simplify

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vera_ewing
  • vera_ewing
how do i do that?
myininaya
  • myininaya
5-8=?
vera_ewing
  • vera_ewing
-3
myininaya
  • myininaya
good what is 1-5?
vera_ewing
  • vera_ewing
-5
myininaya
  • myininaya
you mean -4? \[(-3)^2+(-4)^2\]
vera_ewing
  • vera_ewing
oh yeah
myininaya
  • myininaya
now what is the square of (-3)?
vera_ewing
  • vera_ewing
-6?
myininaya
  • myininaya
what is (-3)(-3)?
vera_ewing
  • vera_ewing
9
myininaya
  • myininaya
yes 9 good what is (-4)^2?
vera_ewing
  • vera_ewing
16
anonymous
  • anonymous
In the interior of the circle
myininaya
  • myininaya
ok so what is 16+9
vera_ewing
  • vera_ewing
25
myininaya
  • myininaya
is 25<81?
vera_ewing
  • vera_ewing
yes
myininaya
  • myininaya
so it is in the interior
vera_ewing
  • vera_ewing
Ohhh ok thanks so much!!! You really helped :)
myininaya
  • myininaya
if we got something > then we would say the exterior if we had got something = to then we would say on the circle
vera_ewing
  • vera_ewing
got it! thank you!
myininaya
  • myininaya
and the center of the circle is definitely not (5,1) since it is (8,5)
vera_ewing
  • vera_ewing
@myininaya can you help with one more? i'll ask a new question :)
myininaya
  • myininaya
just one more then i must get ready for tonight's event

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