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vera_ewing

  • one year ago

The equation of a circle is (x - 8)^2 + (y - 5)^2 = 81. Where is (5, 1) located in relation to the circle? A. In the exterior of the circle B. At the center of the circle C. On the circle D. In the interior of the circle

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  1. myininaya
    • one year ago
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    plug the point into (x-8)^2+(y-5)^2

  2. vera_ewing
    • one year ago
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    @myininaya ok i got (5-8)^2+(1-5)^2

  3. myininaya
    • one year ago
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    simplify

  4. vera_ewing
    • one year ago
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    how do i do that?

  5. myininaya
    • one year ago
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    5-8=?

  6. vera_ewing
    • one year ago
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    -3

  7. myininaya
    • one year ago
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    good what is 1-5?

  8. vera_ewing
    • one year ago
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    -5

  9. myininaya
    • one year ago
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    you mean -4? \[(-3)^2+(-4)^2\]

  10. vera_ewing
    • one year ago
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    oh yeah

  11. myininaya
    • one year ago
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    now what is the square of (-3)?

  12. vera_ewing
    • one year ago
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    -6?

  13. myininaya
    • one year ago
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    what is (-3)(-3)?

  14. vera_ewing
    • one year ago
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    9

  15. myininaya
    • one year ago
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    yes 9 good what is (-4)^2?

  16. vera_ewing
    • one year ago
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    16

  17. Lindsayb12
    • one year ago
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    In the interior of the circle

  18. myininaya
    • one year ago
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    ok so what is 16+9

  19. vera_ewing
    • one year ago
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    25

  20. myininaya
    • one year ago
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    is 25<81?

  21. vera_ewing
    • one year ago
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    yes

  22. myininaya
    • one year ago
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    so it is in the interior

  23. vera_ewing
    • one year ago
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    Ohhh ok thanks so much!!! You really helped :)

  24. myininaya
    • one year ago
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    if we got something > then we would say the exterior if we had got something = to then we would say on the circle

  25. vera_ewing
    • one year ago
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    got it! thank you!

  26. myininaya
    • one year ago
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    and the center of the circle is definitely not (5,1) since it is (8,5)

  27. vera_ewing
    • one year ago
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    @myininaya can you help with one more? i'll ask a new question :)

  28. myininaya
    • one year ago
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    just one more then i must get ready for tonight's event

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