vera_ewing
The equation of a circle is (x - 8)^2 + (y - 5)^2 = 81. Where is (5, 1) located in relation to the circle?
A. In the exterior of the circle
B. At the center of the circle
C. On the circle
D. In the interior of the circle
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myininaya
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plug the point into (x-8)^2+(y-5)^2
vera_ewing
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@myininaya ok i got (5-8)^2+(1-5)^2
myininaya
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simplify
vera_ewing
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how do i do that?
myininaya
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5-8=?
vera_ewing
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-3
myininaya
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good
what is 1-5?
vera_ewing
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-5
myininaya
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you mean -4?
\[(-3)^2+(-4)^2\]
vera_ewing
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oh yeah
myininaya
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now what is the square of (-3)?
vera_ewing
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-6?
myininaya
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what is (-3)(-3)?
vera_ewing
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9
myininaya
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yes 9
good
what is (-4)^2?
vera_ewing
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16
Lindsayb12
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In the interior of the circle
myininaya
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ok so what is 16+9
vera_ewing
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25
myininaya
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is 25<81?
vera_ewing
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yes
myininaya
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so it is in the interior
vera_ewing
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Ohhh ok thanks so much!!! You really helped :)
myininaya
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if we got something > then we would say the exterior
if we had got something = to then we would say on the circle
vera_ewing
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got it! thank you!
myininaya
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and the center of the circle is definitely not (5,1) since it is (8,5)
vera_ewing
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@myininaya can you help with one more? i'll ask a new question :)
myininaya
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just one more
then i must get ready for tonight's event