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vera_ewing

  • 7 months ago

The equation of a circle is (x - 8)^2 + (y - 5)^2 = 81. Where is (5, 1) located in relation to the circle? A. In the exterior of the circle B. At the center of the circle C. On the circle D. In the interior of the circle

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  1. myininaya
    • 7 months ago
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    plug the point into (x-8)^2+(y-5)^2

  2. vera_ewing
    • 7 months ago
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    @myininaya ok i got (5-8)^2+(1-5)^2

  3. myininaya
    • 7 months ago
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    simplify

  4. vera_ewing
    • 7 months ago
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    how do i do that?

  5. myininaya
    • 7 months ago
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    5-8=?

  6. vera_ewing
    • 7 months ago
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    -3

  7. myininaya
    • 7 months ago
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    good what is 1-5?

  8. vera_ewing
    • 7 months ago
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    -5

  9. myininaya
    • 7 months ago
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    you mean -4? \[(-3)^2+(-4)^2\]

  10. vera_ewing
    • 7 months ago
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    oh yeah

  11. myininaya
    • 7 months ago
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    now what is the square of (-3)?

  12. vera_ewing
    • 7 months ago
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    -6?

  13. myininaya
    • 7 months ago
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    what is (-3)(-3)?

  14. vera_ewing
    • 7 months ago
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    9

  15. myininaya
    • 7 months ago
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    yes 9 good what is (-4)^2?

  16. vera_ewing
    • 7 months ago
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    16

  17. Lindsayb12
    • 7 months ago
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    In the interior of the circle

  18. myininaya
    • 7 months ago
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    ok so what is 16+9

  19. vera_ewing
    • 7 months ago
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    25

  20. myininaya
    • 7 months ago
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    is 25<81?

  21. vera_ewing
    • 7 months ago
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    yes

  22. myininaya
    • 7 months ago
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    so it is in the interior

  23. vera_ewing
    • 7 months ago
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    Ohhh ok thanks so much!!! You really helped :)

  24. myininaya
    • 7 months ago
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    if we got something > then we would say the exterior if we had got something = to then we would say on the circle

  25. vera_ewing
    • 7 months ago
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    got it! thank you!

  26. myininaya
    • 7 months ago
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    and the center of the circle is definitely not (5,1) since it is (8,5)

  27. vera_ewing
    • 7 months ago
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    @myininaya can you help with one more? i'll ask a new question :)

  28. myininaya
    • 7 months ago
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    just one more then i must get ready for tonight's event

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