## vera_ewing one year ago The equation of a circle is (x - 8)^2 + (y - 5)^2 = 81. Where is (5, 1) located in relation to the circle? A. In the exterior of the circle B. At the center of the circle C. On the circle D. In the interior of the circle

1. myininaya

plug the point into (x-8)^2+(y-5)^2

2. vera_ewing

@myininaya ok i got (5-8)^2+(1-5)^2

3. myininaya

simplify

4. vera_ewing

how do i do that?

5. myininaya

5-8=?

6. vera_ewing

-3

7. myininaya

good what is 1-5?

8. vera_ewing

-5

9. myininaya

you mean -4? \[(-3)^2+(-4)^2\]

10. vera_ewing

oh yeah

11. myininaya

now what is the square of (-3)?

12. vera_ewing

-6?

13. myininaya

what is (-3)(-3)?

14. vera_ewing

9

15. myininaya

yes 9 good what is (-4)^2?

16. vera_ewing

16

17. Lindsayb12

In the interior of the circle

18. myininaya

ok so what is 16+9

19. vera_ewing

25

20. myininaya

is 25<81?

21. vera_ewing

yes

22. myininaya

so it is in the interior

23. vera_ewing

Ohhh ok thanks so much!!! You really helped :)

24. myininaya

if we got something > then we would say the exterior if we had got something = to then we would say on the circle

25. vera_ewing

got it! thank you!

26. myininaya

and the center of the circle is definitely not (5,1) since it is (8,5)

27. vera_ewing

@myininaya can you help with one more? i'll ask a new question :)

28. myininaya

just one more then i must get ready for tonight's event