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vera_ewing

  • 2 years ago

The equation of a circle is (x - 8)^2 + (y - 5)^2 = 81. Where is (5, 1) located in relation to the circle? A. In the exterior of the circle B. At the center of the circle C. On the circle D. In the interior of the circle

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  1. myininaya
    • 2 years ago
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    plug the point into (x-8)^2+(y-5)^2

  2. vera_ewing
    • 2 years ago
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    @myininaya ok i got (5-8)^2+(1-5)^2

  3. myininaya
    • 2 years ago
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    simplify

  4. vera_ewing
    • 2 years ago
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    how do i do that?

  5. myininaya
    • 2 years ago
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    5-8=?

  6. vera_ewing
    • 2 years ago
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    -3

  7. myininaya
    • 2 years ago
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    good what is 1-5?

  8. vera_ewing
    • 2 years ago
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    -5

  9. myininaya
    • 2 years ago
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    you mean -4? \[(-3)^2+(-4)^2\]

  10. vera_ewing
    • 2 years ago
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    oh yeah

  11. myininaya
    • 2 years ago
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    now what is the square of (-3)?

  12. vera_ewing
    • 2 years ago
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    -6?

  13. myininaya
    • 2 years ago
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    what is (-3)(-3)?

  14. vera_ewing
    • 2 years ago
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    9

  15. myininaya
    • 2 years ago
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    yes 9 good what is (-4)^2?

  16. vera_ewing
    • 2 years ago
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    16

  17. anonymous
    • 2 years ago
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    In the interior of the circle

  18. myininaya
    • 2 years ago
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    ok so what is 16+9

  19. vera_ewing
    • 2 years ago
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    25

  20. myininaya
    • 2 years ago
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    is 25<81?

  21. vera_ewing
    • 2 years ago
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    yes

  22. myininaya
    • 2 years ago
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    so it is in the interior

  23. vera_ewing
    • 2 years ago
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    Ohhh ok thanks so much!!! You really helped :)

  24. myininaya
    • 2 years ago
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    if we got something > then we would say the exterior if we had got something = to then we would say on the circle

  25. vera_ewing
    • 2 years ago
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    got it! thank you!

  26. myininaya
    • 2 years ago
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    and the center of the circle is definitely not (5,1) since it is (8,5)

  27. vera_ewing
    • 2 years ago
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    @myininaya can you help with one more? i'll ask a new question :)

  28. myininaya
    • 2 years ago
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    just one more then i must get ready for tonight's event

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