I have the answer....I just don't understand the steps. Find the limit as x approaches infinity of 1+(a/x)^(bx) - I am putting the original question and the answer from my professor with his explanation in the comments. I just don't understand the steps at all that he has written out.

- anonymous

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- anonymous

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- anonymous

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- anonymous

is the answer \(e^{ab}\)?

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- anonymous

Yes

- anonymous

you can guess it
are you supposed to use l'hopital?

- anonymous

In the comments I put a .png of how he worked it out....I don't understand his substitution with z and how he goes from there....he did say you could use l'hopital but it would be more work???

- anonymous

ooh i see the solution now, sorry
you are supposed to use algebra, and then the fact that
\[e=\lim_{x\to 0}\left(1+x\right)^{\frac{1}{x}}\]

- anonymous

the solution you have written is only algebra

- anonymous

they say put \(z=\frac{a}{x}\) so the piece inside is now \(1+z\)

- anonymous

that part is clear right?

- anonymous

ugh. OK. so what I don't get is the algebra of: this: if z=a/b how does bx=abz^-1?

- anonymous

the exponential notation may have confused you
lets write it without the exponential notation

- anonymous

btw it is not \(z=\frac{a}{b}\) but rather \(z=\frac{a}{x}\) right?

- anonymous

Oh yes, sorry - z=a/x

- anonymous

ok step by step
\[\large z=\frac{a}{x}\] solve for \(x\) you get \[\large x=\frac{a}{z}\] ok so far?

- anonymous

OK

- anonymous

multiply both sides by \(b\) you get
\[\large bx=\frac{ab}{z}\] right?

- anonymous

yep

- anonymous

well that is it then
\[\left(1+\frac{a}{x}\right)^{bx}\] becomes
\[\large (1+z)^{\frac{ab}{z}}\]

- anonymous

ok - I see that now.

- anonymous

done right?

- anonymous

or are there still other algebra steps?

- anonymous

That's it! Thank you. So the fact that e= limx→0 of (1+x)^1/z is just something we need to know, correct? I keep looking for it in my book but can't find it. So, I'll just write it and make a note of it.
Thanks again!!

- anonymous

well i guess so
usually it is written as
\[e=\lim_{x\to \infty}\left(1+\frac{1}{x}\right)^x\] but if you change \(x\) to \(\frac{1}{x}\) then you get
\[e=\lim_{x\to 0}(1+x)^{\frac{1}{x}}\]

- anonymous

Great! Thank you so much for all your help!!

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