anonymous
  • anonymous
Find the standard form and x-intercepts of the function. f(x) = x^2 + 3x + 4 My answers are: standard form -(x + 3/2)^2 + 25/4 and x-intercepts (-4, 0), (1,0) Did I solve this correctly?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
no it"s wrong
anonymous
  • anonymous
can you please help me how to do it?
anonymous
  • anonymous
it become (x+(3/2))^2-(25/4)

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anonymous
  • anonymous
i am sorry I typed the problem wrong: it should be f(x) = -x^2 + 3x + 4
anonymous
  • anonymous
now it's right
anonymous
  • anonymous
oh, thanks

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