leahbernajane
Find the standard form and x-intercepts of the function.
f(x) = x^2 + 3x + 4
My answers are: standard form -(x + 3/2)^2 + 25/4 and x-intercepts (-4, 0), (1,0)
Did I solve this correctly?
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vipul92
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no
it"s wrong
leahbernajane
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can you please help me how to do it?
vipul92
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it become (x+(3/2))^2-(25/4)
leahbernajane
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i am sorry I typed the problem wrong: it should be f(x) = -x^2 + 3x + 4
vipul92
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now it's right
leahbernajane
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oh, thanks