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leahbernajane

  • one year ago

Find the standard form and x-intercepts of the function. f(x) = x^2 + 3x + 4 My answers are: standard form -(x + 3/2)^2 + 25/4 and x-intercepts (-4, 0), (1,0) Did I solve this correctly?

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  1. vipul92
    • one year ago
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    no it"s wrong

  2. leahbernajane
    • one year ago
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    can you please help me how to do it?

  3. vipul92
    • one year ago
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    it become (x+(3/2))^2-(25/4)

  4. leahbernajane
    • one year ago
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    i am sorry I typed the problem wrong: it should be f(x) = -x^2 + 3x + 4

  5. vipul92
    • one year ago
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    now it's right

  6. leahbernajane
    • one year ago
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    oh, thanks

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