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HourglassMage

  • one year ago

Please see the attached file. I WILL MEDAL AND FAN, PLEASE HELP!!

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  1. HourglassMage
    • one year ago
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    http://i30.photobucket.com/albums/c324/JMLOVER2121/Number2.gif

  2. HourglassMage
    • one year ago
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    Find the value of x in the figure below. Show all steps.

  3. HourglassMage
    • one year ago
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    The larger arc is 158°

  4. HourglassMage
    • one year ago
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    I got an answer of 5.78°

  5. HourglassMage
    • one year ago
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    is this correct?

  6. ScarlettBlack
    • one year ago
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    Just a second.

  7. HourglassMage
    • one year ago
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    tyt :)

  8. ScarlettBlack
    • one year ago
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    I can give you a formula that will help you find the answer. (9x - 5) = 1/2 (larger arc - smaller arc) So 158-64 = 94 / (1/2) = 47 angle (9x - 5) = 47 so 47 - 5 = 42 42 / 9 = 4.6666666667 or you can round to 4.70 You can check it.

  9. ScarlettBlack
    • one year ago
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    Oh sorry it's actually my bad. You take 47 and then you add 5 and then you divide by 9 and that's x

  10. HourglassMage
    • one year ago
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    right, yeah, I was just going to say that would make my answer 5.78 right?

  11. ScarlettBlack
    • one year ago
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    No, that would make your answer 6

  12. HourglassMage
    • one year ago
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    52/9 = 5.78....unless they wanted me to round up to the nearest whole number...

  13. ScarlettBlack
    • one year ago
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    ahhh sorry so yeah. You're original answer is correct. I don't know why but for some reason today I'm just being extra... well I feel dumber. Is the question multiple choice?

  14. HourglassMage
    • one year ago
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    lol, it's fine no it's free response

  15. HourglassMage
    • one year ago
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    this is my work: (9x - 5)º = (1/2)(158° - 64º) (9x - 5)º = (1/2)(94) (9x - 5)º = 47° 9x + (-5 + 5) = (47 + 5)° 9x = 52 9x/9 = 52/9 x = 5.78 x = 5.78

  16. ScarlettBlack
    • one year ago
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    Well you can wait to see if anyone else will answer but I would say go with your gut. I'm not really sure how else to put it. Sorry if I wasn't of help.

  17. ScarlettBlack
    • one year ago
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    Yup, that looks about right though.

  18. HourglassMage
    • one year ago
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    It's fine, mostly I just wanted to make sure my equation was right thnx for your help! :D

  19. ScarlettBlack
    • one year ago
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    Sure thing!

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