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MotasemAlSayed
 one year ago
Find the solution of the Laplace’s equation in the square region 0<x, y<pi subject to the boundary conditions { u(x,0 ) =f(x), u(x,pi)=f(x), u(0,y)=f(y), u(pi,y)=f(y), 0<y<pi and 0<x<pi ...
where f(z) = z for ( 0<z < pi/2) and f(z) = pi z for (pi/2 < z < pi)
MotasemAlSayed
 one year ago
Find the solution of the Laplace’s equation in the square region 0<x, y<pi subject to the boundary conditions { u(x,0 ) =f(x), u(x,pi)=f(x), u(0,y)=f(y), u(pi,y)=f(y), 0<y<pi and 0<x<pi ... where f(z) = z for ( 0<z < pi/2) and f(z) = pi z for (pi/2 < z < pi)

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experimentX
 one year ago
Best ResponseYou've already chosen the best response.0lol ... this looks like awful amount of work? how far how you got with this.

MotasemAlSayed
 one year ago
Best ResponseYou've already chosen the best response.0hhh..the problem here that we have the interval on z axis

MotasemAlSayed
 one year ago
Best ResponseYou've already chosen the best response.0I 'm still trying :(
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