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anonymous
 2 years ago
Find the solution of the Laplace’s equation in the square region 0<x, y<pi subject to the boundary conditions { u(x,0 ) =f(x), u(x,pi)=f(x), u(0,y)=f(y), u(pi,y)=f(y), 0<y<pi and 0<x<pi ...
where f(z) = z for ( 0<z < pi/2) and f(z) = pi z for (pi/2 < z < pi)
anonymous
 2 years ago
Find the solution of the Laplace’s equation in the square region 0<x, y<pi subject to the boundary conditions { u(x,0 ) =f(x), u(x,pi)=f(x), u(0,y)=f(y), u(pi,y)=f(y), 0<y<pi and 0<x<pi ... where f(z) = z for ( 0<z < pi/2) and f(z) = pi z for (pi/2 < z < pi)

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experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0lol ... this looks like awful amount of work? how far how you got with this.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hhh..the problem here that we have the interval on z axis
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