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anonymous
 2 years ago
Use the compound interest formula,
Alexia has $4864.77 in her money market account currently. If the annual interest rate is 3.9%, and the interest is compounded twice per year, how much money will be in her account after 2 years?
A. $4,149.57
B. $5,244.22
C. $5,255.47
D. $15,733.31
anonymous
 2 years ago
Use the compound interest formula, Alexia has $4864.77 in her money market account currently. If the annual interest rate is 3.9%, and the interest is compounded twice per year, how much money will be in her account after 2 years? A. $4,149.57 B. $5,244.22 C. $5,255.47 D. $15,733.31

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@texaschic101 can you help me again??

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@noneyabusiness can you help me??

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@uri can you help me??

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@Xan can you help me??

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Your equation is \[A = 4864.77(1 + \frac{ 0.039 }{ 2 })\ ^{\left( 2 \times 2 \right)}\] Can you solve it?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[A = 4864.77(1 + \frac{ 0.039 }{ 2 })^{\left( 2 \times 2 \right)}\] \[A = 4864.77(1 + 0.0195)^{\left( 4\right)}\] \[A = 4864.77(1.0195)^{\left( 4\right)}\] \[A = 4864.77(1.0803113)\] \[A = 5255.466\] \[A = 5255.47\] So your answer is C.
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