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Hi :-)
what is your constraint?

have you tried it yet?

\[\frac{ -b+\sqrt{b ^{2}-4ac} }{ 2a } = k \frac{ -b-\sqrt{b ^{2}-4ac} }{ 2a }\]

That's how I started, but I got stuck, and it gets kinda messy

let's play with variable roots, assume that roots are \(x_1\) and \(x_2\)

what are the expressions for \(x_1 x_2\) and \(x_1+x_2\) in terms of quadratic coefficients?

Not sure I understand what you mean? Two roots are in ratio 1:k, so x1=kx2

do u know about formula for the Sum and product of the roots of a quadratic?

Don't think so

I will teach you then :-)

Ok :) thats reasonably

am i clear nick?

can u calculate \(x_1 x_2\)? give it a try :-)

One sec

c/a

you are great :-)

But I still don't see how can I use that in this particular question :D

\[\frac{ x _{1} }{ x _{2} }=k\] That can be useful, should I try that?

I don't see the way out

you don't need to involve b formula again :-)

I also tried x1/x2 with -b formula straight away but it get even more complicated.

How? What do I do with x1 and x2

please show me the steps :-)

This is ridiculous, now I got that \[b ^{2}=c^{2}\]
http://prntscr.com/3n5k5k

try again :-) you are close to the answer

check your steps again, be careful :-)

No improvements

is this equation clear for you: \[x_2^2(1+k)^2=\frac{b^2}{a^2} \ \ \ \star\]

Seriously, I can't spot the mistake

Absolutely

let me know if there is a doubt on it :-)

I see it now, I literally ignored multiplication.
Thank you :) I got it now