Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

|dw:1401422933563:dw|

six trignometric functions?

yes. sin, tan, sec, cos, cot, csc

ok plug into calculator using the inverse buton

to find all six? Can you baby it down for me haha

okay lol

so first look at your triangle its 35 in x and -37 in y

so enter 35/-37 in your calculator, and then do cos-1 (35/-37)

thats a button on your calculator cos inverse

do the same for sin and tan

cos=2.811295299?

make sure you are using degree mode

ok it is now cos=161.0753556

that answer is in radians which is fine too if your teacher wants that

alright thats one, now do the rest

remember that
1/sin= csc
1/cos=sec
1/tan=cot

by the way that is not the only solution,

ya it usually accepts fractions.

|dw:1401423483117:dw|

So i just plugged in -37/\[\sqrt{2594}\]

is it in quadrant 2 not 4?

i dont know its your choice what do you want??

well the cos is positive and the tan is negative. so wont that be quad 4?

yeah

ok now what would the hypotenus equal?

do Pythagorean thm

|dw:1401423730828:dw|

ok

i get square root of 2594

is that right? I might be doing my calcs wrong

looks about right

|dw:1401423880441:dw|

so would sin of theta=37/square root of 2594

the hypotenuse should be roughly sqrt2*36

it says it is wrong

square root of 36?

its -37

no nvm that, its just an approximation i dont have calc

cos is adj/hyp
you labeled the initial triangle a bit wrong

okay do it over

can you show me the right triangle?

|dw:1401424044893:dw|

good

now find the opp measurement of the angle theta |dw:1401424168943:dw|

and how did you get that?

use the theorem we talked about last question

you are given cos is 35/37

right right right. got it

none of those are negative?

right cos is positive not negative

sin is negative

so you will definitely get a negative number for that opp measurement to theta

i got 12

and it should really be -12

35^2+b^2=37^2

b^2=144 b=12?

or b=-12
we will go with b=-12 because we were given cos is + tan is - which makes sin -

ok. so sin =-12/37

and yes

that clarifies completely. what about this one?
tan θ is undefined. constraint: π ≤ θ ≤ 2π

find the six.

remember tan theta = sin theta/costheta
so its undefin when cos theta= 0 which is at?

so each one would be undefined?

no just the tan and the cot

well atually no cot is fine

how do i find the rest?

have to first find this

tan theta= sin theta/cos theta => undefined when denominator =0
where cos theta =0

solve for cos theta = 0 , when theta is in that given interval pi to 2pi

would it be 2pi/pi?

no