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oksuz_

  • 11 months ago

help!!

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  1. oksuz_
    • 11 months ago
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    show that the sequence of function given by \[fn(x)=nlog(1+\sin(x/n)) \] converges point wise to the identity function f(x)=x anyone has an idea ?

  2. BSwan
    • 11 months ago
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    like \(f_1(x)= log (1+sin x )\) \(f_2(x)=f_1+2 log (1+sin x/2 )\) ... ?!

  3. klimenkov
    • 11 months ago
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    Use this: \(\sin x = x + O(x^3), \, x\rightarrow 0\). \[\lim_{n\rightarrow \infty}n\log\left(1 + \sin\left( x/n\right)\right) = \lim_{n\rightarrow \infty}\log\left(1 + x/n\right)^n\]

  4. BSwan
    • 11 months ago
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    it would be something like this :- |dw:1401617819184:dw|

  5. oksuz_
    • 10 months ago
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    @klimenkov at your solution last part equals e^x right? then when x goes to infinite e^x also goes to infinite.. should we consider identity function's interval here that is convergent ??

  6. klimenkov
    • 10 months ago
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    \(x\) is a fixed point and \(n\rightarrow \infty\). So it will converge for every finite \(x\). \[\log e^x = x.\]

  7. oksuz_
    • 10 months ago
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    @klimenkov thank you..

  8. oksuz_
    • 10 months ago
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    @BSwan thank you

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