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LilySwan
 one year ago
find dy/dx if
(ax+cx^5)/kx^8
LilySwan
 one year ago
find dy/dx if (ax+cx^5)/kx^8

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myininaya
 one year ago
Best ResponseYou've already chosen the best response.1a,c, and k are constants?

micahwood50
 one year ago
Best ResponseYou've already chosen the best response.1Just use quotient rule.

LilySwan
 one year ago
Best ResponseYou've already chosen the best response.0got stucked at one point

micahwood50
 one year ago
Best ResponseYou've already chosen the best response.1\(\dfrac{d}{dx} \dfrac{f(x)}{g(x)} = \dfrac{f'(x)g(x)  f(x)g'(x)}{(g(x))^2}\)

LilySwan
 one year ago
Best ResponseYou've already chosen the best response.0why can we solve the numerator part first

micahwood50
 one year ago
Best ResponseYou've already chosen the best response.1treat constant as if they are just "number", and not variable.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1@LilySwan Did you have a problem with finding derivative of the top or the bottom? That is what you need to plug into @micahwood50 's formula. what do you mean solve the numerator? You shouldn't be solving. You should be differentiating it. What is the derivative of the top part of your fraction?

LilySwan
 one year ago
Best ResponseYou've already chosen the best response.0for the upper part 5cx^4 +a

micahwood50
 one year ago
Best ResponseYou've already chosen the best response.1Right f'(x) = a+5cx^4

micahwood50
 one year ago
Best ResponseYou've already chosen the best response.1Can you find g'(x)?

LilySwan
 one year ago
Best ResponseYou've already chosen the best response.0for the lower part it will be 8kx^7

micahwood50
 one year ago
Best ResponseYou've already chosen the best response.1Yep. So you have f(x) = ax+cx^5, f'(x) = a+5cx^4, g(x) = kx^8, g'(x) = 8kx^7 Just plug these in formula given above then simplify.

micahwood50
 one year ago
Best ResponseYou've already chosen the best response.1Can you do it? @LilySwan

LilySwan
 one year ago
Best ResponseYou've already chosen the best response.0i was told to use this formula \[\frac{ d }{ dx }(\frac{ u}{ v }) =\frac{ (v \frac{ du }{ dx })(u \frac{ dv }{ dx }) }{ v^2 }\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1same formula different notation

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[\dfrac{d}{dx} \dfrac{f(x)}{g(x)} = \dfrac{f'(x)g(x)  f(x)g'(x)}{(g(x))^2} \] if you want you can replace the f's with u's the g's with v's the ' things with d/dx and you have the same formula

LilySwan
 one year ago
Best ResponseYou've already chosen the best response.0\[5cx^4+a.kx^8  ax+cx^5. 8kx^7/(kx^8)^2\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{(5cx^4+a)(kx^8)(ax+cx^5)(8kx^7)}{(kx^8)^2}\] i think this is what you mean

LilySwan
 one year ago
Best ResponseYou've already chosen the best response.0what should i be doing the next

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1guess you could multiply things out on top and also use law of exponents on the bottom to simplify the bottom
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