A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
find dy/dx if
(ax+cx^5)/kx^8
anonymous
 one year ago
find dy/dx if (ax+cx^5)/kx^8

This Question is Closed

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1a,c, and k are constants?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just use quotient rule.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0got stucked at one point

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\dfrac{d}{dx} \dfrac{f(x)}{g(x)} = \dfrac{f'(x)g(x)  f(x)g'(x)}{(g(x))^2}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why can we solve the numerator part first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0treat constant as if they are just "number", and not variable.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1@LilySwan Did you have a problem with finding derivative of the top or the bottom? That is what you need to plug into @micahwood50 's formula. what do you mean solve the numerator? You shouldn't be solving. You should be differentiating it. What is the derivative of the top part of your fraction?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for the upper part 5cx^4 +a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right f'(x) = a+5cx^4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for the lower part it will be 8kx^7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep. So you have f(x) = ax+cx^5, f'(x) = a+5cx^4, g(x) = kx^8, g'(x) = 8kx^7 Just plug these in formula given above then simplify.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you do it? @LilySwan

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i was told to use this formula \[\frac{ d }{ dx }(\frac{ u}{ v }) =\frac{ (v \frac{ du }{ dx })(u \frac{ dv }{ dx }) }{ v^2 }\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1same formula different notation

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[\dfrac{d}{dx} \dfrac{f(x)}{g(x)} = \dfrac{f'(x)g(x)  f(x)g'(x)}{(g(x))^2} \] if you want you can replace the f's with u's the g's with v's the ' things with d/dx and you have the same formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[5cx^4+a.kx^8  ax+cx^5. 8kx^7/(kx^8)^2\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{(5cx^4+a)(kx^8)(ax+cx^5)(8kx^7)}{(kx^8)^2}\] i think this is what you mean

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what should i be doing the next

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1guess you could multiply things out on top and also use law of exponents on the bottom to simplify the bottom
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.