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myininaya Group TitleBest ResponseYou've already chosen the best response.1
a,c, and k are constants?
 5 months ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
Just use quotient rule.
 5 months ago

LilySwan Group TitleBest ResponseYou've already chosen the best response.0
got stucked at one point
 5 months ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
\(\dfrac{d}{dx} \dfrac{f(x)}{g(x)} = \dfrac{f'(x)g(x)  f(x)g'(x)}{(g(x))^2}\)
 5 months ago

LilySwan Group TitleBest ResponseYou've already chosen the best response.0
why can we solve the numerator part first
 5 months ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
treat constant as if they are just "number", and not variable.
 5 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
@LilySwan Did you have a problem with finding derivative of the top or the bottom? That is what you need to plug into @micahwood50 's formula. what do you mean solve the numerator? You shouldn't be solving. You should be differentiating it. What is the derivative of the top part of your fraction?
 5 months ago

LilySwan Group TitleBest ResponseYou've already chosen the best response.0
for the upper part 5cx^4 +a
 5 months ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
Right f'(x) = a+5cx^4
 5 months ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
Can you find g'(x)?
 5 months ago

LilySwan Group TitleBest ResponseYou've already chosen the best response.0
for the lower part it will be 8kx^7
 5 months ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
Yep. So you have f(x) = ax+cx^5, f'(x) = a+5cx^4, g(x) = kx^8, g'(x) = 8kx^7 Just plug these in formula given above then simplify.
 5 months ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.1
Can you do it? @LilySwan
 5 months ago

LilySwan Group TitleBest ResponseYou've already chosen the best response.0
trying wait
 5 months ago

LilySwan Group TitleBest ResponseYou've already chosen the best response.0
i was told to use this formula \[\frac{ d }{ dx }(\frac{ u}{ v }) =\frac{ (v \frac{ du }{ dx })(u \frac{ dv }{ dx }) }{ v^2 }\]
 5 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
same formula different notation
 5 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\dfrac{d}{dx} \dfrac{f(x)}{g(x)} = \dfrac{f'(x)g(x)  f(x)g'(x)}{(g(x))^2} \] if you want you can replace the f's with u's the g's with v's the ' things with d/dx and you have the same formula
 5 months ago

LilySwan Group TitleBest ResponseYou've already chosen the best response.0
\[5cx^4+a.kx^8  ax+cx^5. 8kx^7/(kx^8)^2\]
 5 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{(5cx^4+a)(kx^8)(ax+cx^5)(8kx^7)}{(kx^8)^2}\] i think this is what you mean
 5 months ago

LilySwan Group TitleBest ResponseYou've already chosen the best response.0
what should i be doing the next
 5 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
guess you could multiply things out on top and also use law of exponents on the bottom to simplify the bottom
 5 months ago
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