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Luigi0210
 8 months ago
Best ResponseYou've already chosen the best response.4\[\LARGE \int_{1}^{0}~\frac{e^{1/x}}{x^3}~dx\]

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2try letting u=1/x so x=1/u

Joshyboi25tolyfe
 8 months ago
Best ResponseYou've already chosen the best response.0Guys guys... In the eyes of god, mathematics doesn't exist! Now, let's all hold hands and pray.

ganeshie8
 8 months ago
Best ResponseYou've already chosen the best response.1yeah u can't avoid parts i think

dan815
 8 months ago
Best ResponseYou've already chosen the best response.1mathematics is a language and God gave us languages

Luigi0210
 8 months ago
Best ResponseYou've already chosen the best response.4\[\LARGE \int_{1}^{0}~\frac{e^{1/x}}{x^3}~dx\] \[\LARGE =\int_{1}^{0}~\frac{1}{x}~e^{1/x}~\frac{1}{x^2}~dx\] \(\Large u=1/x\) and \(\Large du=\frac{1}{x^2}dx\) \[\LARGE \int_{1}^{0}~ue^udu\] And then use parts like dan said?

Luigi0210
 8 months ago
Best ResponseYou've already chosen the best response.4*\[\LARGE \int_{1}^{0}~ue^udu\]

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2you should have an improper integral

Luigi0210
 8 months ago
Best ResponseYou've already chosen the best response.4\[\LARGE \LARGE \lim_{t \rightarrow 0} \int_{1}^{t}~ue^udu~\]?

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2of x is between 1 and 0 and u=1/x dw:1402252341171:dw

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2as we approach 0 from the left what is u getting approaching?

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2dw:1402252495152:dw

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2we are looking to the left of 0 because our interval is 1 to 0 none of our values occur to the right of 0 so we won't bother to look there

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2i'm asking him to evaluate the following: \[\lim_{x \rightarrow 0^}\frac{1}{x}\]

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2lugi0210 just read the graph above as our x values get near the 0 number (from the left) what do your u values (or if you want call them y values) do?

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2right so i'm going to change one thing in your lim from earlier \[\LARGE \LARGE \lim_{t \rightarrow  \infty} \int\limits_{1}^{t}~ue^udu~ \]

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2i think there should be a negative in front of that

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2\[ \LARGE \LARGE \lim_{t \rightarrow  \infty} \int\limits\limits_{1}^{t}~ue^udu~\]

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2you know from the du=1/x^2 dx thing

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2now use integration by parts then evaluate the limit

Luigi0210
 8 months ago
Best ResponseYou've already chosen the best response.4Alright, I see it now, it was the limits that was throwing me off >_< Thank you myininaya :)

ganeshie8
 8 months ago
Best ResponseYou've already chosen the best response.1if u feel lazy about changing the bounds, you may try below : 1) Find the indefinite integral first 2) plugin the bounds

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2@Luigi0210 did you get it?
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