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Luigi0210
 11 months ago
Integration:
Luigi0210
 11 months ago
Integration:

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Luigi0210
 11 months ago
Best ResponseYou've already chosen the best response.4\[\LARGE \int_{1}^{0}~\frac{e^{1/x}}{x^3}~dx\]

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2try letting u=1/x so x=1/u

Joshyboi25tolyfe
 11 months ago
Best ResponseYou've already chosen the best response.0Guys guys... In the eyes of god, mathematics doesn't exist! Now, let's all hold hands and pray.

ganeshie8
 11 months ago
Best ResponseYou've already chosen the best response.1yeah u can't avoid parts i think

dan815
 11 months ago
Best ResponseYou've already chosen the best response.1mathematics is a language and God gave us languages

dan815
 11 months ago
Best ResponseYou've already chosen the best response.1so shut your 3.14 hole

Luigi0210
 11 months ago
Best ResponseYou've already chosen the best response.4\[\LARGE \int_{1}^{0}~\frac{e^{1/x}}{x^3}~dx\] \[\LARGE =\int_{1}^{0}~\frac{1}{x}~e^{1/x}~\frac{1}{x^2}~dx\] \(\Large u=1/x\) and \(\Large du=\frac{1}{x^2}dx\) \[\LARGE \int_{1}^{0}~ue^udu\] And then use parts like dan said?

Luigi0210
 11 months ago
Best ResponseYou've already chosen the best response.4*\[\LARGE \int_{1}^{0}~ue^udu\]

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2you should have an improper integral

Luigi0210
 11 months ago
Best ResponseYou've already chosen the best response.4\[\LARGE \LARGE \lim_{t \rightarrow 0} \int_{1}^{t}~ue^udu~\]?

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2of x is between 1 and 0 and u=1/x dw:1402252341171:dw

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2as we approach 0 from the left what is u getting approaching?

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2dw:1402252495152:dw

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2we are looking to the left of 0 because our interval is 1 to 0 none of our values occur to the right of 0 so we won't bother to look there

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2i'm asking him to evaluate the following: \[\lim_{x \rightarrow 0^}\frac{1}{x}\]

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2lugi0210 just read the graph above as our x values get near the 0 number (from the left) what do your u values (or if you want call them y values) do?

Luigi0210
 11 months ago
Best ResponseYou've already chosen the best response.4\(\Large \infty\)?

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2right so i'm going to change one thing in your lim from earlier \[\LARGE \LARGE \lim_{t \rightarrow  \infty} \int\limits_{1}^{t}~ue^udu~ \]

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2i think there should be a negative in front of that

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2\[ \LARGE \LARGE \lim_{t \rightarrow  \infty} \int\limits\limits_{1}^{t}~ue^udu~\]

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2you know from the du=1/x^2 dx thing

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2now use integration by parts then evaluate the limit

Luigi0210
 11 months ago
Best ResponseYou've already chosen the best response.4Alright, I see it now, it was the limits that was throwing me off >_< Thank you myininaya :)

ganeshie8
 11 months ago
Best ResponseYou've already chosen the best response.1if u feel lazy about changing the bounds, you may try below : 1) Find the indefinite integral first 2) plugin the bounds

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2@Luigi0210 did you get it?
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