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\[\LARGE \int_{-1}^{0}~\frac{e^{1/x}}{x^3}~dx\]

sub u = 1/x

try letting u=1/x
so x=1/u

then do parts

Guys guys... In the eyes of god, mathematics doesn't exist! Now, let's all hold hands and pray.

yeah u can't avoid parts i think

mathematics is a language and God gave us languages

so shut your 3.14 hole

LOLOL ^

:)

*\[\LARGE -\int_{-1}^{0}~ue^udu\]

you should have an improper integral

\[\LARGE \LARGE \lim_{t \rightarrow 0} \int_{-1}^{t}~ue^udu~\]?

of x is between -1 and 0
and u=1/x
|dw:1402252341171:dw|

as we approach 0 from the left what is u getting approaching?

|dw:1402252495152:dw|

i'm asking him to evaluate the following:
\[\lim_{x \rightarrow 0^-}\frac{1}{x}\]

\(\Large -\infty\)?

i think there should be a negative in front of that

\[- \LARGE \LARGE \lim_{t \rightarrow - \infty} \int\limits\limits_{-1}^{t}~ue^udu~\]

you know from the du=-1/x^2 dx thing

now use integration by parts
then evaluate the limit

Alright, I see it now, it was the limits that was throwing me off >_<
Thank you myininaya :)

@Luigi0210 did you get it?