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Taxia2 Group Title

how would you solve this rational equation?

  • 4 months ago
  • 4 months ago

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  1. Taxia2 Group Title
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    \[\sqrt{15x}(\sqrt{18x}+\sqrt{15x})\]

    • 4 months ago
  2. myininaya Group Title
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    There is no equation to solve? Are you to multiply?

    • 4 months ago
  3. Taxia2 Group Title
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    oops, it is supposed to be simplified!

    • 4 months ago
  4. Taxia2 Group Title
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    but that is the equation, I have the answer, but I am unsure how to get to it.

    • 4 months ago
  5. myininaya Group Title
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    So we want to simplify the expression. Again there is no equation. Just so you know assuming we have x>=0 you can write \[\sqrt{18x}=\sqrt{18} \sqrt{x}\] and you can also do the same for the other terms too.

    • 4 months ago
  6. myininaya Group Title
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    Do you know how to multiply \[\sqrt{x} \cdot \sqrt{x}?\]

    • 4 months ago
  7. Taxia2 Group Title
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    wouldn't that just be x?

    • 4 months ago
  8. myininaya Group Title
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    right another question! Do you know the distributive property?

    • 4 months ago
  9. Taxia2 Group Title
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    I do

    • 4 months ago
  10. myininaya Group Title
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    so you know if you have a(b+c) you can do ab+ac

    • 4 months ago
  11. myininaya Group Title
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    so you have \[\sqrt{15} \sqrt{x}(\sqrt{18} \sqrt{x}+\sqrt{15} \sqrt{x})\]

    • 4 months ago
  12. myininaya Group Title
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    so you can treat the thing on the outside of the parenthesis just like that a above

    • 4 months ago
  13. Taxia2 Group Title
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    yes, but wouldn't all of the square roots cancel out? I tried this but the answer i received had no square roots in it. But the answer that is given does...

    • 4 months ago
  14. Taxia2 Group Title
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    wait, I got it!!!

    • 4 months ago
  15. Taxia2 Group Title
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    I think...

    • 4 months ago
  16. myininaya Group Title
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    Is 15*18 a perfect square? I don't think it is. So you would have at least one square root in your answer. What do you think the answer is?

    • 4 months ago
  17. Taxia2 Group Title
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    well, the given answer is \[3x \sqrt{30} +15x\] so first I simplified what i could inside the parenthesis and got \[\sqrt{15x} (3\sqrt{2x} + \sqrt{15x})\] and then I distributed (Like you said!) and got this \[3\sqrt{30x ^{2}} + \sqrt{15^{2}x ^{2}}\] then I canceled out the roots (like you said) and got the answer!

    • 4 months ago
  18. myininaya Group Title
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    beautiful you didn't need my help

    • 4 months ago
  19. Taxia2 Group Title
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    I did! If I hadn't had it I probably would have given up (as cliche as that sounds) Thank you so much for working me through it!

    • 4 months ago
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