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xBeEnchantedx Group Title

How do you solve: logbase5 (square root of x+3) = logbase5 (4)?

  • one month ago
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  1. myininaya Group Title
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    this means your insides have to be equal

    • one month ago
  2. xBeEnchantedx Group Title
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    \[\log_{5} (\sqrt{x+3})=\log_{5} (4)\] <- thats a better way to view the equation.

    • one month ago
  3. myininaya Group Title
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    Since y=log_5(x) is a one to one function if you have f(a)=f(b) then this implies a=b

    • one month ago
  4. myininaya Group Title
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    like basically i'm telling you that \[\sqrt{x+3}=4 \text{ now solve }\]

    • one month ago
  5. xBeEnchantedx Group Title
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    Ohhh thank you. I accidentally put the wrong exponent when trying to get rid of the square root, which through off my calculations. Thank you :D

    • one month ago
  6. myininaya Group Title
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    coolness

    • one month ago
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