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xBeEnchantedx
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How do you solve: logbase5 (square root of x+3) = logbase5 (4)?
 5 months ago
 5 months ago
xBeEnchantedx Group Title
How do you solve: logbase5 (square root of x+3) = logbase5 (4)?
 5 months ago
 5 months ago

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myininaya Group TitleBest ResponseYou've already chosen the best response.2
this means your insides have to be equal
 5 months ago

xBeEnchantedx Group TitleBest ResponseYou've already chosen the best response.0
\[\log_{5} (\sqrt{x+3})=\log_{5} (4)\] < thats a better way to view the equation.
 5 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
Since y=log_5(x) is a one to one function if you have f(a)=f(b) then this implies a=b
 5 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
like basically i'm telling you that \[\sqrt{x+3}=4 \text{ now solve }\]
 5 months ago

xBeEnchantedx Group TitleBest ResponseYou've already chosen the best response.0
Ohhh thank you. I accidentally put the wrong exponent when trying to get rid of the square root, which through off my calculations. Thank you :D
 5 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
coolness
 5 months ago
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