Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
xBeEnchantedx
Group Title
How do you solve: logbase5 (square root of x+3) = logbase5 (4)?
 4 months ago
 4 months ago
xBeEnchantedx Group Title
How do you solve: logbase5 (square root of x+3) = logbase5 (4)?
 4 months ago
 4 months ago

This Question is Closed

myininaya Group TitleBest ResponseYou've already chosen the best response.2
this means your insides have to be equal
 4 months ago

xBeEnchantedx Group TitleBest ResponseYou've already chosen the best response.0
\[\log_{5} (\sqrt{x+3})=\log_{5} (4)\] < thats a better way to view the equation.
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
Since y=log_5(x) is a one to one function if you have f(a)=f(b) then this implies a=b
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
like basically i'm telling you that \[\sqrt{x+3}=4 \text{ now solve }\]
 4 months ago

xBeEnchantedx Group TitleBest ResponseYou've already chosen the best response.0
Ohhh thank you. I accidentally put the wrong exponent when trying to get rid of the square root, which through off my calculations. Thank you :D
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.2
coolness
 4 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.