Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

xBeEnchantedx

  • one year ago

How do you solve: logbase5 (square root of x+3) = logbase5 (4)?

  • This Question is Closed
  1. myininaya
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    this means your insides have to be equal

  2. xBeEnchantedx
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\log_{5} (\sqrt{x+3})=\log_{5} (4)\] <- thats a better way to view the equation.

  3. myininaya
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Since y=log_5(x) is a one to one function if you have f(a)=f(b) then this implies a=b

  4. myininaya
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    like basically i'm telling you that \[\sqrt{x+3}=4 \text{ now solve }\]

  5. xBeEnchantedx
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ohhh thank you. I accidentally put the wrong exponent when trying to get rid of the square root, which through off my calculations. Thank you :D

  6. myininaya
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    coolness

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy