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xBeEnchantedx
 8 months ago
How do you solve: logbase5 (square root of x+3) = logbase5 (4)?
xBeEnchantedx
 8 months ago
How do you solve: logbase5 (square root of x+3) = logbase5 (4)?

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myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2this means your insides have to be equal

xBeEnchantedx
 8 months ago
Best ResponseYou've already chosen the best response.0\[\log_{5} (\sqrt{x+3})=\log_{5} (4)\] < thats a better way to view the equation.

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2Since y=log_5(x) is a one to one function if you have f(a)=f(b) then this implies a=b

myininaya
 8 months ago
Best ResponseYou've already chosen the best response.2like basically i'm telling you that \[\sqrt{x+3}=4 \text{ now solve }\]

xBeEnchantedx
 8 months ago
Best ResponseYou've already chosen the best response.0Ohhh thank you. I accidentally put the wrong exponent when trying to get rid of the square root, which through off my calculations. Thank you :D
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