## xBeEnchantedx 2 years ago How do you solve: logbase5 (square root of x+3) = logbase5 (4)?

1. myininaya

this means your insides have to be equal

2. xBeEnchantedx

$\log_{5} (\sqrt{x+3})=\log_{5} (4)$ <- thats a better way to view the equation.

3. myininaya

Since y=log_5(x) is a one to one function if you have f(a)=f(b) then this implies a=b

4. myininaya

like basically i'm telling you that $\sqrt{x+3}=4 \text{ now solve }$

5. xBeEnchantedx

Ohhh thank you. I accidentally put the wrong exponent when trying to get rid of the square root, which through off my calculations. Thank you :D

6. myininaya

coolness