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Basically is there any factoring you can do?

Yes that's it and simplify iit

yep then plug in 5 to resulting function that is continuous at 5

you can share your steps with me if you want

would it be 10/0?

not 10/0 nope
show me what you did to get that

(x+25)(x-25)/x-5

that isn't how you factor x^2-25

x^2-a^2=(x-a)(x+a)
you have
x^2-5^2=(x-5)(x+5)

OH (x+5)(x-5)

right but what do yo notice about the top and bottom (As far as factors go)

and you have (x+5)(x-5)/(x-5)

You can cancel

(x+5)

right
you basically get rid of the discontinuity so you can plug in x=5

so 10

right

Thank you!!

np