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anonymous
 one year ago
Find the limit of the function algebraically.
lim(x > 5)
x^225/x5
anonymous
 one year ago
Find the limit of the function algebraically. lim(x > 5) x^225/x5

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myininaya
 one year ago
Best ResponseYou've already chosen the best response.1So I think you mean (x^225)/(x5) right? This expression does not exist at x=5 because when you plug in 5 you get something/0 Now when you have 0/0 that means the limit can exist Is there any algebra you can perform to force a function that is continuous at 5?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Basically is there any factoring you can do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes that's it and simplify iit

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1yep then plug in 5 to resulting function that is continuous at 5

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1you can share your steps with me if you want

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1not 10/0 nope show me what you did to get that

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1that isn't how you factor x^225

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1x^2a^2=(xa)(x+a) you have x^25^2=(x5)(x+5)

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1right but what do yo notice about the top and bottom (As far as factors go)

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1and you have (x+5)(x5)/(x5)

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1right you basically get rid of the discontinuity so you can plug in x=5
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