anonymous
  • anonymous
Find the limit of the function algebraically. lim(x -> 5) x^2-25/x-5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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myininaya
  • myininaya
So I think you mean (x^2-25)/(x-5) right? This expression does not exist at x=5 because when you plug in 5 you get something/0 Now when you have 0/0 that means the limit can exist Is there any algebra you can perform to force a function that is continuous at 5?
myininaya
  • myininaya
Basically is there any factoring you can do?
anonymous
  • anonymous
Yes that's it and simplify iit

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myininaya
  • myininaya
yep then plug in 5 to resulting function that is continuous at 5
myininaya
  • myininaya
you can share your steps with me if you want
anonymous
  • anonymous
would it be 10/0?
myininaya
  • myininaya
not 10/0 nope show me what you did to get that
anonymous
  • anonymous
(x+25)(x-25)/x-5
myininaya
  • myininaya
that isn't how you factor x^2-25
myininaya
  • myininaya
x^2-a^2=(x-a)(x+a) you have x^2-5^2=(x-5)(x+5)
anonymous
  • anonymous
OH (x+5)(x-5)
myininaya
  • myininaya
right but what do yo notice about the top and bottom (As far as factors go)
myininaya
  • myininaya
and you have (x+5)(x-5)/(x-5)
anonymous
  • anonymous
You can cancel
anonymous
  • anonymous
(x+5)
myininaya
  • myininaya
right you basically get rid of the discontinuity so you can plug in x=5
anonymous
  • anonymous
so 10
myininaya
  • myininaya
right
anonymous
  • anonymous
Thank you!!
myininaya
  • myininaya
np

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