A community for students.
Here's the question you clicked on:
 0 viewing
Owlcoffee
 11 months ago
so I was working on a math exercise and I got a little stuck on this part:
\[x ^{2}+(\frac{ (2x \lambda)^{2} }{ 16 })+\frac{ ( \lambda  4)x }{ 2 }+\frac{ ( \lambda 16)(2x \lambda) }{ 8 }+ \lambda = 0\]
Owlcoffee
 11 months ago
so I was working on a math exercise and I got a little stuck on this part: \[x ^{2}+(\frac{ (2x \lambda)^{2} }{ 16 })+\frac{ ( \lambda  4)x }{ 2 }+\frac{ ( \lambda 16)(2x \lambda) }{ 8 }+ \lambda = 0\]

This Question is Closed

Owlcoffee
 11 months ago
Best ResponseYou've already chosen the best response.0my objectuve is to simply it.

sweetburger
 11 months ago
Best ResponseYou've already chosen the best response.0get those denominators the same

Owlcoffee
 11 months ago
Best ResponseYou've already chosen the best response.0yes, I multiplied the whole equation by 16: \[16x ^{2}+(2x \lambda)^{2}+(8)(x)( \lambda  4)+(2)( \lambda 16)(2x \lambda)+16 \lambda=0\]

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2Are you trying to solve the equation for x?

Owlcoffee
 11 months ago
Best ResponseYou've already chosen the best response.0No no, The original excercise is about some different. on the process I got that equation with two variables and what I'm trying to do is form a quadratic equation with it. in terms of x. Lambda is just a arbitrary constant.

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.2so you are trying to set it up as ax^2+bx+c=0?

Owlcoffee
 11 months ago
Best ResponseYou've already chosen the best response.0yes. If possibly, I'd have to search another way of I can't set it up like that.

Owlcoffee
 11 months ago
Best ResponseYou've already chosen the best response.0okay, I could pretty much do it: \[20x ^{2}+(16 \lambda 96)x+( \lambda ^{2}+48 \lambda )=0\] :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.