• Owlcoffee
so I was working on a math exercise and I got a little stuck on this part: $x ^{2}+(\frac{ (2x- \lambda)^{2} }{ 16 })+\frac{ (- \lambda - 4)x }{ 2 }+\frac{ (- \lambda -16)(2x- \lambda) }{ 8 }+ \lambda = 0$
Mathematics

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