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drumminboy918 Group Title

I bet no one can solve this equation.

  • 5 months ago
  • 5 months ago

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  1. drumminboy918 Group Title
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    5x^-2y^10 over 2x^-1(-3x^-3y^-1)^-2

    • 5 months ago
  2. myininaya Group Title
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    Because there is no equation to solve. :p

    • 5 months ago
  3. myininaya Group Title
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    Do you mean to simplify the expression.

    • 5 months ago
  4. drumminboy918 Group Title
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    Yes, straight from an SAT study book

    • 5 months ago
  5. DawnR Group Title
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    this is http://media.tumblr.com/tumblr_memy8mw86I1qc9tqw.gif

    • 5 months ago
  6. myininaya Group Title
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    I'm going to phrase this using latex just to make sure I understand what you have written: \[\frac{5x^{-2}y^{10}}{2x^{-1}(-3x^{-3}y^{-1})^{-2}}\]

    • 5 months ago
  7. drumminboy918 Group Title
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    @DawnR XD hahaha

    • 5 months ago
  8. myininaya Group Title
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    It is very important to recall the law of exponents here. I will write some useful ones here regarding this problem: \[x^{-n}=\frac{1}{x^n}\] \[\frac{1}{x^{-n}}=x^{n}\] \[x^{1}=x\] \[x^0=1 \text{ note: } x \neq 0\] \[(a^rb^tc^s)n=a^{rn}b^{tn}c^{sn}\]

    • 5 months ago
  9. myininaya Group Title
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    also \[x^nx^m=x^{m+n} \text{ and } \frac{x^n}{x^m}=x^{n-m}\]

    • 5 months ago
  10. myininaya Group Title
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    These are good lows to recall for this problem.

    • 5 months ago
  11. myininaya Group Title
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    also that one law is a little broken let me rewrite it

    • 5 months ago
  12. myininaya Group Title
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    \[(a^rb^tc^s)^n=a^{rn}b^{tn}c^{sn}\]

    • 5 months ago
  13. myininaya Group Title
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    can you use this last law here on the problem anywhere that you can see?

    • 5 months ago
  14. drumminboy918 Group Title
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    I'm not asking this question because I need help, I am asking to see if someone for actually get it

    • 5 months ago
  15. drumminboy918 Group Title
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    Can*

    • 5 months ago
  16. myininaya Group Title
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    |dw:1403479310371:dw| I will give you a hint: look in the circle below:

    • 5 months ago
  17. myininaya Group Title
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    |dw:1403479439985:dw|

    • 5 months ago
  18. myininaya Group Title
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    that looks exactly like that law on the left hand side

    • 5 months ago
  19. myininaya Group Title
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    now use the right hand side to rewrite this thing in the circle

    • 5 months ago
  20. myininaya Group Title
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    I do get it And I can help you

    • 5 months ago
  21. drumminboy918 Group Title
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    I don't need help, I wanted to see if anyone can actually get it. Its not HW or anything, just a fun equation

    • 5 months ago
  22. myininaya Group Title
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    Ok, well I do get it...

    • 5 months ago
  23. drumminboy918 Group Title
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    I never said you didn't...

    • 5 months ago
  24. myininaya Group Title
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    I guess I don't understand what you mean then.

    • 5 months ago
  25. drumminboy918 Group Title
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    Ok solve the equation then

    • 5 months ago
  26. myininaya Group Title
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    I will help you to do just that.

    • 5 months ago
  27. myininaya Group Title
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    If you are posting this as a challenge, I think I will let someone else do it.

    • 5 months ago
  28. myininaya Group Title
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    This problem is not challenging to me. I'm sorry.

    • 5 months ago
  29. mathmale Group Title
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    Drummer: If you want feedback on the solution of this problem, please share with the rest of us the work that you yourself have done. if you're not willing to provide such feedback, then, frankly, it sounds as that you may be trying to get someone else to do your work for you...and that'd be true regardless of whether you're doing this problem for the challenge or for an assignment.

    • 5 months ago
  30. drumminboy918 Group Title
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    Do you want the website I got this from?? I just wanted to see if people could actual do it

    • 5 months ago
  31. mathmale Group Title
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    Again, please try doing it yourself first. If you want feedback on your work after you've done that, fine. To paraphrase you, I just want to see whether YOU can actually solve this problem at hand, before I invest time and effort in this problem solving myself. Isn't that fair?

    • 5 months ago
  32. drumminboy918 Group Title
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    Again, this is just a friendly question. It does not come from a quiz, worksheet, or homework of any kind. I simply goggled "Very hard math equations" and copy and pasted one from a website to give a fun challenge to people.

    • 5 months ago
  33. mathmale Group Title
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    Fine, Drummin. Take the challenge and do the problem yourself, as far as you can. Then I'd be happy to give you feedback on how I think we might finish solving the problem. Remember that everyone here on OpenStudy is here voluntarily, and thus is free to help or not help, get involved or not get involved, as he or she wishes. I've made my wants clear: show what you have done and list any questions you may have, before I get involved. Glad you're curious and motivated and eager to solve challenging questions. Still, I feel more obligated to help those here on OpenStudy who try their best to get started out in their problem solving and share what they have done with me up front.

    • 5 months ago
  34. drumminboy918 Group Title
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    I have no clue how to do this, I don't even know where to start

    • 5 months ago
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