A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 6 months ago
Determine if the following trajectory lies on a circle...
I start with a vector <sint+sqrt(3)cost, sqrt(3)sintcost>
I am down to 2(cos^2)t+4(sin^2)t+2sintcost2sqrt(3)sintcost but am just bad enough at trig to not know what to do from here to find what the radius is this trajectory lies on...
 6 months ago
Determine if the following trajectory lies on a circle... I start with a vector <sint+sqrt(3)cost, sqrt(3)sintcost> I am down to 2(cos^2)t+4(sin^2)t+2sintcost2sqrt(3)sintcost but am just bad enough at trig to not know what to do from here to find what the radius is this trajectory lies on...

This Question is Open

quekyuxuan
 6 months ago
Best ResponseYou've already chosen the best response.0Your algebra is wrong; if you square the formulas for x and y separately and add them, the sintcost terms will cancel, and you'll be left with 4(sin^2 t + cos^2 t), so the magnitude of your vector is constant for all values of t

phi
 5 months ago
Best ResponseYou've already chosen the best response.0you have a vector v= <x,y> where both x and y are functions of t the length of the vector is \[ \sqrt{v \cdot v} = \sqrt{x^2+y^2} \] if this length is constant then we know all the points traced out by v over time must lie on the circumference of a circle.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.