A community for students.

    Here's the question you clicked on:

    55 members online
    • 0 replying
    • 0 viewing


    • one year ago

    Determine if the following trajectory lies on a circle... I start with a vector <sint+sqrt(3)cost, sqrt(3)sint-cost> I am down to 2(cos^2)t+4(sin^2)t+2sintcost-2sqrt(3)sintcost but am just bad enough at trig to not know what to do from here to find what the radius is this trajectory lies on...

    • This Question is Open
    1. quekyuxuan
      • one year ago
      Best Response
      You've already chosen the best response.
      Medals 0

      Your algebra is wrong; if you square the formulas for x and y separately and add them, the sintcost terms will cancel, and you'll be left with 4(sin^2 t + cos^2 t), so the magnitude of your vector is constant for all values of t

    2. phi
      • one year ago
      Best Response
      You've already chosen the best response.
      Medals 0

      you have a vector v= <x,y> where both x and y are functions of t the length of the vector is \[ \sqrt{v \cdot v} = \sqrt{x^2+y^2} \] if this length is constant then we know all the points traced out by v over time must lie on the circumference of a circle.

    3. Not the answer you are looking for?
      Search for more explanations.

      • Attachments:

    Ask your own question

    Sign Up
    Find more explanations on OpenStudy
    Privacy Policy

    Your question is ready. Sign up for free to start getting answers.

    spraguer (Moderator)
    5 → View Detailed Profile

    is replying to Can someone tell me what button the professor is hitting...


    • Teamwork 19 Teammate
    • Problem Solving 19 Hero
    • You have blocked this person.
    • ✔ You're a fan Checking fan status...

    Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

    This is the testimonial you wrote.
    You haven't written a testimonial for Owlfred.