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Issy14
Group Title
Let w(x) = g(g(x)). Find:
(a) w(1) (b) w(2) (c) w(3)
somebody please help, I have no idea what to do.
 3 months ago
 3 months ago
Issy14 Group Title
Let w(x) = g(g(x)). Find: (a) w(1) (b) w(2) (c) w(3) somebody please help, I have no idea what to do.
 3 months ago
 3 months ago

This Question is Open

geerky42 Group TitleBest ResponseYou've already chosen the best response.0
well, we need to know what g(x) is. were you given function of g?
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
@geerky42 one second going to post the image
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
dw:1404857483770:dw
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
These are the directions: In Problems 57–60, use Figure 3.17 and the chain rule to estimate the derivative, or state why the chain rule does not apply. The graph of f(x) has a sharp corner at x = 2.
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
If you have time , I could really use assistance on this question. @TuringTest
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
@tkhunny If you have time, I could really use assistance on this question
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
I think i figured out g(x) = 1x+4 f(x) is not continuous it has a breat at (0,2) therefore if i try to get the slope they are going to have the same magnitude but different signs f(x)=4x or f(x)= 4x
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
I know the chain rule by heart, I don't know how to apply here. f'(x)= f'(g(x)) x g'(x)
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
Help in need of a mentor please. @Taylor<3sRin @myko @ganeshie8
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
help @jdoe0001
 3 months ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.0
\(f(x) = 2x2+4\)
 3 months ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.0
hmm, wait. exactly what do you need help with?
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
with the problem given
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
it comes with the graph and the instructions.
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
How did you find f(x). ? did you just transform it from the original function x
 3 months ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.0
yeah, that's how I figure it out
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
alright, is that the usual approach?
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
am I correct on g(x)?
 3 months ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.0
well, i don't know what's your given problems are. are you asked to take derivative of f(x) using chain rule, or state why chain rule does not apply?
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
both In Problems 57–60, use Figure 3.17 and the chain rule to estimate the derivative, or state why the chain rule does not apply. The graph of f(x) has a sharp corner at x = 2. 60. Let w(x) = g(g(x)). Find: (a) w(1) (b) w(2) (c) w(3)
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
that's the problem and then they give you the graph
 3 months ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.0
ok i see. well, we managed to figure f(x) out by using transformation from parent function, so we have f(x) = 2x2+4 we can take derivative of f(x) because it is continuous. just not differentiable at break point. so we can let h(x) = 2x+4 and j(x) = x2 so we have \(f'(x) = h'(~j(x)~)~j'(x)\)
 3 months ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.0
PS: \[\large\dfrac{d}{dx}x = \dfrac{x}{x}\]
 3 months ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.0
on second thought, you was asked to estimate the derivative, but what we are doing is finding the actual derivative. hmm, not sure what to do here. do you have any idea?
 3 months ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.0
what does "estimate the derivative" mean?
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
basically, when they ask us to do that they want an approximate value not the absolute value
 3 months ago

geerky42 Group TitleBest ResponseYou've already chosen the best response.0
huh, i am sorry, this problem confused me, because i don't see how chain rule can be apply to estimate value from given graph? so i am not sure... sorry.
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
it's ok, I'm confused as well, thank you for your help.
 3 months ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
i think you are thinking too hard for this one
 3 months ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
from the picture we see \(g(1)=3\) and \(g(3)=1\) so \(g(g(1))=g(3)=1\)
 3 months ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
similarly \(g(2)=2\) so \(g(g(2))=g(2)=2\)
 3 months ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
as for the derivative, \[\left(g(g(x)\right)'=g(g(x))g'(x)\] by the chain rule
 3 months ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
ok that was a mistake!!
 3 months ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
\[\left(g(g(x)\right)'=g'(g(x))g'(x)\]
 3 months ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
then \[w'(1)=g'(g(1))\times g'(1)=1\times 1=1\]
 3 months ago

febylailani Group TitleBest ResponseYou've already chosen the best response.1
dw:1404869501887:dw
 3 months ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
which should not surprise you since \(g(g(x))=x\)
 3 months ago

Issy14 Group TitleBest ResponseYou've already chosen the best response.2
then there was no need to find out the function of each one? I did that before but I thought that it was too simple. I will continue reading your answer, thank you. @satellite73 and @febylailani
 3 months ago
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