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anonymous
 one year ago
Let w(x) = g(g(x)). Find:
(a) w(1) (b) w(2) (c) w(3)
somebody please help, I have no idea what to do.
anonymous
 one year ago
Let w(x) = g(g(x)). Find: (a) w(1) (b) w(2) (c) w(3) somebody please help, I have no idea what to do.

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geerky42
 one year ago
Best ResponseYou've already chosen the best response.0well, we need to know what g(x) is. were you given function of g?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@geerky42 one second going to post the image

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1404857483770:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0These are the directions: In Problems 57–60, use Figure 3.17 and the chain rule to estimate the derivative, or state why the chain rule does not apply. The graph of f(x) has a sharp corner at x = 2.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you have time , I could really use assistance on this question. @TuringTest

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@tkhunny If you have time, I could really use assistance on this question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think i figured out g(x) = 1x+4 f(x) is not continuous it has a breat at (0,2) therefore if i try to get the slope they are going to have the same magnitude but different signs f(x)=4x or f(x)= 4x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know the chain rule by heart, I don't know how to apply here. f'(x)= f'(g(x)) x g'(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Help in need of a mentor please. @Taylor<3sRin @myko @ganeshie8

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0hmm, wait. exactly what do you need help with?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0with the problem given

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it comes with the graph and the instructions.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How did you find f(x). ? did you just transform it from the original function x

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0yeah, that's how I figure it out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright, is that the usual approach?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0am I correct on g(x)?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0well, i don't know what's your given problems are. are you asked to take derivative of f(x) using chain rule, or state why chain rule does not apply?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0both In Problems 57–60, use Figure 3.17 and the chain rule to estimate the derivative, or state why the chain rule does not apply. The graph of f(x) has a sharp corner at x = 2. 60. Let w(x) = g(g(x)). Find: (a) w(1) (b) w(2) (c) w(3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's the problem and then they give you the graph

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0ok i see. well, we managed to figure f(x) out by using transformation from parent function, so we have f(x) = 2x2+4 we can take derivative of f(x) because it is continuous. just not differentiable at break point. so we can let h(x) = 2x+4 and j(x) = x2 so we have \(f'(x) = h'(~j(x)~)~j'(x)\)

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0PS: \[\large\dfrac{d}{dx}x = \dfrac{x}{x}\]

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0on second thought, you was asked to estimate the derivative, but what we are doing is finding the actual derivative. hmm, not sure what to do here. do you have any idea?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0what does "estimate the derivative" mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0basically, when they ask us to do that they want an approximate value not the absolute value

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0huh, i am sorry, this problem confused me, because i don't see how chain rule can be apply to estimate value from given graph? so i am not sure... sorry.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it's ok, I'm confused as well, thank you for your help.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think you are thinking too hard for this one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0from the picture we see \(g(1)=3\) and \(g(3)=1\) so \(g(g(1))=g(3)=1\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0similarly \(g(2)=2\) so \(g(g(2))=g(2)=2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0as for the derivative, \[\left(g(g(x)\right)'=g(g(x))g'(x)\] by the chain rule

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok that was a mistake!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\left(g(g(x)\right)'=g'(g(x))g'(x)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then \[w'(1)=g'(g(1))\times g'(1)=1\times 1=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1404869501887:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0which should not surprise you since \(g(g(x))=x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then there was no need to find out the function of each one? I did that before but I thought that it was too simple. I will continue reading your answer, thank you. @satellite73 and @febylailani
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