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anonymous
 2 years ago
Why does the gravitational acceleration (g) decrease at the distance further from 4500 m below the sea level? and what is the value of g is at the center of the earth?
anonymous
 2 years ago
Why does the gravitational acceleration (g) decrease at the distance further from 4500 m below the sea level? and what is the value of g is at the center of the earth?

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0The value of g at the center of the earth is approximately 0. If we take a hollow sphere as in the diagram, all the particles of the sphere exert a force \[G m_{1}m_{2} \div r ^{2}\] These forces can be cancelled up resulting in no force acting at the center. When we consider infinite number of spheres from r=0 to r=R(R=Radius of Earth), we get a resultant force of 0. dw:1404915773985:dw

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0May I suggest another perspective? Newton developed the concept that gravitational FORCES are related not only to the square of the radius of a planetary body, but also related to it's mass. This in turn affects the acceleration of a freefalling object. The average radius of the Earth is 6367 kilometers. 4.5 kilometers (4500 meters) below sea level means that the radius of the Earth at that spot is (6367  4.5) = 6362.5 km, so the radius has decreased and the gravitational force should therefore be reduced by a small fraction. 6367^2 = 40538689 6362.5^2 = 40481406.25 If the radius zero, then gravitational forces should be zero. Of course, no one has been there so this remains our understanding at this time. I hope that I have helped and not hindered your understanding of this problem.
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