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melissa2
 10 months ago
How many grams of Na2CO3 are required to make 0.100 moles of Na2CO3? @Abmon98
melissa2
 10 months ago
How many grams of Na2CO3 are required to make 0.100 moles of Na2CO3? @Abmon98

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Abmon98
 10 months ago
Best ResponseYou've already chosen the best response.1Number of Moles=Mass(g)/Molar Mass(g/mol) Look at your periodic table for each element atomic weight in Na2CO3 Na: 23 gram C: 12 gram O: 16 gram Molar Mass(g/mol)=(23*2)+(12*1)+(16*3)=88 gram Number of Moles=Mass(g)/Molar Mass(g/mol) Rearrange your equation Mass(g)=Molar Mass(g/mol)*Number of Moles Mass(g)=0.100*88=8.8

melissa2
 10 months ago
Best ResponseYou've already chosen the best response.0Thanks For explain And in thatn How many actual molecules of methane are present in 32 grams of methane?

Abmon98
 10 months ago
Best ResponseYou've already chosen the best response.1methane molar mass is 16 12+(1*4)=16 use number of moles=mass(g)/molar mass(g/mol) plug in you given mass 32/16= 2 mole of methane 1 mole consists of 6.02*10^23 molecules (Avogadro constant number) 2 moles consist of x molecules x=2*6.02*10^23/1 molecule

Somy
 10 months ago
Best ResponseYou've already chosen the best response.1mole= mass/Molecular mass u have mass as 32g and molecular mass of Methane u can find from periodic table after you found mole  multiply it by Avogadro number which is \(6.02 \times 10^23\)

melissa2
 10 months ago
Best ResponseYou've already chosen the best response.0so the answer is 19,264,000 or not?

Somy
 10 months ago
Best ResponseYou've already chosen the best response.1no you calculated it wrong

Somy
 10 months ago
Best ResponseYou've already chosen the best response.1put ( \(6.02 \times 10^23\) ) in brackets like this and the multiply by 2
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