A community for students.
Here's the question you clicked on:
 0 viewing
melissa2
 9 months ago
How many grams of Na2CO3 are required to make 0.100 moles of Na2CO3? @Abmon98
melissa2
 9 months ago
How many grams of Na2CO3 are required to make 0.100 moles of Na2CO3? @Abmon98

This Question is Open

Abmon98
 9 months ago
Best ResponseYou've already chosen the best response.1Number of Moles=Mass(g)/Molar Mass(g/mol) Look at your periodic table for each element atomic weight in Na2CO3 Na: 23 gram C: 12 gram O: 16 gram Molar Mass(g/mol)=(23*2)+(12*1)+(16*3)=88 gram Number of Moles=Mass(g)/Molar Mass(g/mol) Rearrange your equation Mass(g)=Molar Mass(g/mol)*Number of Moles Mass(g)=0.100*88=8.8

melissa2
 9 months ago
Best ResponseYou've already chosen the best response.0Thanks For explain And in thatn How many actual molecules of methane are present in 32 grams of methane?

Abmon98
 9 months ago
Best ResponseYou've already chosen the best response.1methane molar mass is 16 12+(1*4)=16 use number of moles=mass(g)/molar mass(g/mol) plug in you given mass 32/16= 2 mole of methane 1 mole consists of 6.02*10^23 molecules (Avogadro constant number) 2 moles consist of x molecules x=2*6.02*10^23/1 molecule

Somy
 9 months ago
Best ResponseYou've already chosen the best response.1mole= mass/Molecular mass u have mass as 32g and molecular mass of Methane u can find from periodic table after you found mole  multiply it by Avogadro number which is \(6.02 \times 10^23\)

melissa2
 9 months ago
Best ResponseYou've already chosen the best response.0so the answer is 19,264,000 or not?

Somy
 9 months ago
Best ResponseYou've already chosen the best response.1no you calculated it wrong

Somy
 9 months ago
Best ResponseYou've already chosen the best response.1put ( \(6.02 \times 10^23\) ) in brackets like this and the multiply by 2
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.