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melissa2
Group Title
How many grams of Na2CO3 are required to make 0.100 moles of Na2CO3? @Abmon98
 16 days ago
 16 days ago
melissa2 Group Title
How many grams of Na2CO3 are required to make 0.100 moles of Na2CO3? @Abmon98
 16 days ago
 16 days ago

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Abmon98 Group TitleBest ResponseYou've already chosen the best response.1
Number of Moles=Mass(g)/Molar Mass(g/mol) Look at your periodic table for each element atomic weight in Na2CO3 Na: 23 gram C: 12 gram O: 16 gram Molar Mass(g/mol)=(23*2)+(12*1)+(16*3)=88 gram Number of Moles=Mass(g)/Molar Mass(g/mol) Rearrange your equation Mass(g)=Molar Mass(g/mol)*Number of Moles Mass(g)=0.100*88=8.8
 16 days ago

melissa2 Group TitleBest ResponseYou've already chosen the best response.0
Thanks For explain And in thatn How many actual molecules of methane are present in 32 grams of methane?
 16 days ago

Abmon98 Group TitleBest ResponseYou've already chosen the best response.1
methane molar mass is 16 12+(1*4)=16 use number of moles=mass(g)/molar mass(g/mol) plug in you given mass 32/16= 2 mole of methane 1 mole consists of 6.02*10^23 molecules (Avogadro constant number) 2 moles consist of x molecules x=2*6.02*10^23/1 molecule
 16 days ago

Somy Group TitleBest ResponseYou've already chosen the best response.1
mole= mass/Molecular mass u have mass as 32g and molecular mass of Methane u can find from periodic table after you found mole  multiply it by Avogadro number which is \(6.02 \times 10^23\)
 16 days ago

melissa2 Group TitleBest ResponseYou've already chosen the best response.0
so the answer is 19,264,000 or not?
 16 days ago

Somy Group TitleBest ResponseYou've already chosen the best response.1
no you calculated it wrong
 16 days ago

Somy Group TitleBest ResponseYou've already chosen the best response.1
put ( \(6.02 \times 10^23\) ) in brackets like this and the multiply by 2
 16 days ago
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