## melissa2 Group Title How many grams of Na2CO3 are required to make 0.100 moles of Na2CO3? @Abmon98 2 months ago 2 months ago

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1. Abmon98 Group Title

Number of Moles=Mass(g)/Molar Mass(g/mol) Look at your periodic table for each element atomic weight in Na2CO3 Na: 23 gram C: 12 gram O: 16 gram Molar Mass(g/mol)=(23*2)+(12*1)+(16*3)=88 gram Number of Moles=Mass(g)/Molar Mass(g/mol) Rearrange your equation Mass(g)=Molar Mass(g/mol)*Number of Moles Mass(g)=0.100*88=8.8

2. melissa2 Group Title

Thanks For explain And in thatn How many actual molecules of methane are present in 32 grams of methane?

3. Abmon98 Group Title

methane molar mass is 16 12+(1*4)=16 use number of moles=mass(g)/molar mass(g/mol) plug in you given mass 32/16= 2 mole of methane 1 mole consists of 6.02*10^23 molecules (Avogadro constant number) 2 moles consist of x molecules x=2*6.02*10^23/1 molecule

4. Somy Group Title

mole= mass/Molecular mass u have mass as 32g and molecular mass of Methane u can find from periodic table after you found mole - multiply it by Avogadro number which is $$6.02 \times 10^23$$

5. melissa2 Group Title

so the answer is 19,264,000 or not?

6. Somy Group Title

no you calculated it wrong

7. Somy Group Title

put ( $$6.02 \times 10^23$$ ) in brackets like this and the multiply by 2