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mathisblockingmypath
Group Title
A line passes through (1, –5) and (–3, 7).Write an equation for the line in pointslope form.
Rewrite the equation in slopeintercept form.
 one month ago
 one month ago
mathisblockingmypath Group Title
A line passes through (1, –5) and (–3, 7).Write an equation for the line in pointslope form. Rewrite the equation in slopeintercept form.
 one month ago
 one month ago

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jdoe0001 Group TitleBest ResponseYou've already chosen the best response.1
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 1}}\quad ,&{\color{blue}{ 05}})\quad &({\color{red}{ 3}}\quad ,&{\color{blue}{ 7}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}{\color{blue}{ y_1}}}{{\color{red}{ x_2}}{\color{red}{ x_1}}} \\ \quad \\ y{\color{blue}{ y_1}}={\color{green}{ m}}(x{\color{red}{ x_1}})\qquad \textit{plug in the values }\\ \qquad \uparrow\\ \textit{pointslope form}\) and to get it in slopeintercept form , \(\bf y = mx+b\) just solve it for "y"
 one month ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.1
hmm got a 0 there for no good reason =) anyhow \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 1}}\quad ,&{\color{blue}{ 5}})\quad &({\color{red}{ 3}}\quad ,&{\color{blue}{ 7}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}{\color{blue}{ y_1}}}{{\color{red}{ x_2}}{\color{red}{ x_1}}} \\ \quad \\ y{\color{blue}{ y_1}}={\color{green}{ m}}(x{\color{red}{ x_1}})\qquad \textit{plug in the values }\\ \qquad \uparrow\\ \textit{pointslope form}\)
 one month ago

mathisblockingmypath Group TitleBest ResponseYou've already chosen the best response.0
okay so how would the final answer look
 one month ago
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