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mathisblockingmypath
Group Title
A line passes through (1, –5) and (–3, 7).Write an equation for the line in pointslope form.
Rewrite the equation in slopeintercept form.
 3 months ago
 3 months ago
mathisblockingmypath Group Title
A line passes through (1, –5) and (–3, 7).Write an equation for the line in pointslope form. Rewrite the equation in slopeintercept form.
 3 months ago
 3 months ago

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jdoe0001 Group TitleBest ResponseYou've already chosen the best response.1
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 1}}\quad ,&{\color{blue}{ 05}})\quad &({\color{red}{ 3}}\quad ,&{\color{blue}{ 7}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}{\color{blue}{ y_1}}}{{\color{red}{ x_2}}{\color{red}{ x_1}}} \\ \quad \\ y{\color{blue}{ y_1}}={\color{green}{ m}}(x{\color{red}{ x_1}})\qquad \textit{plug in the values }\\ \qquad \uparrow\\ \textit{pointslope form}\) and to get it in slopeintercept form , \(\bf y = mx+b\) just solve it for "y"
 3 months ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.1
hmm got a 0 there for no good reason =) anyhow \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 1}}\quad ,&{\color{blue}{ 5}})\quad &({\color{red}{ 3}}\quad ,&{\color{blue}{ 7}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}{\color{blue}{ y_1}}}{{\color{red}{ x_2}}{\color{red}{ x_1}}} \\ \quad \\ y{\color{blue}{ y_1}}={\color{green}{ m}}(x{\color{red}{ x_1}})\qquad \textit{plug in the values }\\ \qquad \uparrow\\ \textit{pointslope form}\)
 3 months ago

mathisblockingmypath Group TitleBest ResponseYou've already chosen the best response.0
okay so how would the final answer look
 3 months ago
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