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anonymous
 one year ago
show that the linearization of sin(x) at 0= the linearization of tan(x) at 0
anonymous
 one year ago
show that the linearization of sin(x) at 0= the linearization of tan(x) at 0

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Linearization of sin(x) at x=0: L= f(0)f'(0)*(x0) L= 0  cos(0*)x *the derivative of sin is cos L= x Linearization of tan(x) at x=0 L= f(0)f'(0)*x L=0f'(sec^2(0))*x *the derivative of tan is sec^2 L=x
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