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  • one year ago

lim x approaches 0 (sinx-tanx)

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  1. kloby
    • one year ago
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    Sine and Tangent are both continuous at a neighbourhood of 0 therefore we can just plug in the value 0: \[\lim_{x\to0}(\sin x-\tan x)=(\sin 0-\tan 0)=0-0=0\]

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