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anonymous
 2 years ago
lim x approaches 0 (sinxtanx)
anonymous
 2 years ago
lim x approaches 0 (sinxtanx)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sine and Tangent are both continuous at a neighbourhood of 0 therefore we can just plug in the value 0: \[\lim_{x\to0}(\sin x\tan x)=(\sin 0\tan 0)=00=0\]
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