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Sandis
There are 5 beaches competing to be the family friendliest beach according to one travel magazine. If only the top 3 are ranked - first, second, and third - how many different ways can the list appear? A. 15 ways B. 30 ways C. 60 ways D. 10 ways
Can someone help me with this problem?
Any of the 5 beaches could be at first place. Keeping this in mind, we see that any 4 of the beaches left could be second place. So there are 5*4=20 combinations of first and second place. By the same argument, any of the 3 beaches left could be third place. In total, this gives us 60 different lists, since 60=5*4*3.
@dape that's right :)