anonymous
  • anonymous
Can someone explain to me what's happening in this final step? I've seen the answer, but I don't undertstand how to get it! http://imgur.com/GSuuI0l
MIT 18.01 Single Variable Calculus (OCW)
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
In the numerator there is derivative of the denominator so we can apply ln( ) law
phi
  • phi
if you multiply the top by 3, you get exactly the derivative of the bottom so put a ⅓ out front , and multiply the top by 3 you now have \[ \frac{1}{3} \int \frac{du}{u} = \frac{1}{3}\ln(u) \] notice we can write the above as \[ \frac{1}{3} \int \frac{du}{u} = \int \frac{du}{3u} \] it looks like they want to see 3(x^3+ 6x^2 +3x+8) or 3x^3 +18x^2 + 9x + 24 in the "box"

Looking for something else?

Not the answer you are looking for? Search for more explanations.