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anonymous
 one year ago
A statement Sn about the positive integers is given. Write statements S1, S2, and S3, and show that each of these statements is true.
Sn: 12 + 42 + 72 + . . . + (3n  2)2 = (n(〖6n〗^23n1))/2
anonymous
 one year ago
A statement Sn about the positive integers is given. Write statements S1, S2, and S3, and show that each of these statements is true. Sn: 12 + 42 + 72 + . . . + (3n  2)2 = (n(〖6n〗^23n1))/2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just @sloths this is my question do u see this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0gimme a second i'll look

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this question doesn't make any sense. not sure if its the wording or copy paste wasn't good for it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its 1^2 and 4^2 not 12 or 42

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0u want me to send u a snapshot or attach the actual file

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0either would be great

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0k ill attach the file

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep, which number is it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i'm sorry my computer keeps crashing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh thx no problem, u can always emailo me at msm6205@gmail.com if u cant help me here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0were u able to look at the problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@heroromen11 hey u can help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0plus i really don't understand this.. i'm not in pre calc yet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh thx for trying though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u help me with any other problem in the packet
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