notmathnerd
Eliminate the parameter.
x = t + 4, y = t^2



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myininaya
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solve x=t+4 for t
then replace the t in y=t^2
and then done

myininaya
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@notmathnerd do you understand?

notmathnerd
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yes I do thank you

notmathnerd
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would it be y=x^2  16 ? @myininaya

myininaya
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hmmm
not correct but i think it is because you forgot a simple algebraic rule (and don't worry a lot of people forget it)

myininaya
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(ab)^2 doesn't meant a^2b^2

myininaya
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(ab)^2 means (ab)(ab)

myininaya
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so what am i saying is i'm pretty sure you got this far y=(x4)^2
but you didn't expand the (x4)^2 correctly
that is all

notmathnerd
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So the answer is actually x^2  8x + 16?

myininaya
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the answer is actually y=x^28x+16

notmathnerd
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ok thank you