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notmathnerd

  • one year ago

Eliminate the parameter. x = t + 4, y = t^2

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  1. myininaya
    • one year ago
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    solve x=t+4 for t then replace the t in y=t^2 and then done

  2. myininaya
    • one year ago
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    @notmathnerd do you understand?

  3. notmathnerd
    • one year ago
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    yes I do thank you

  4. notmathnerd
    • one year ago
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    would it be y=x^2 - 16 ? @myininaya

  5. myininaya
    • one year ago
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    hmmm not correct but i think it is because you forgot a simple algebraic rule (and don't worry a lot of people forget it)

  6. myininaya
    • one year ago
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    (a-b)^2 doesn't meant a^2-b^2

  7. myininaya
    • one year ago
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    (a-b)^2 means (a-b)(a-b)

  8. myininaya
    • one year ago
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    so what am i saying is i'm pretty sure you got this far y=(x-4)^2 but you didn't expand the (x-4)^2 correctly that is all

  9. notmathnerd
    • one year ago
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    So the answer is actually x^2 - 8x + 16?

  10. myininaya
    • one year ago
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    the answer is actually y=x^2-8x+16

  11. notmathnerd
    • one year ago
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    ok thank you

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