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amyna
Group Title
3+2i / 32i leave answer in a+bi form
the answer is 5/13 + 12/13i , but i keep getting a different answer please help me!!
 one month ago
 one month ago
amyna Group Title
3+2i / 32i leave answer in a+bi form the answer is 5/13 + 12/13i , but i keep getting a different answer please help me!!
 one month ago
 one month ago

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myininaya Group TitleBest ResponseYou've already chosen the best response.1
so you have 3+2i/32i or do you mean (3+2i)/(32i)?
 one month ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
i think you mean the latter \[\text{ so we have } \frac{3+2i}{32i}\] do you know to put it in a+bi form the first step you must take is to multiply both top and bottom by bottom's conjugate
 one month ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
do you know what the conjugate of 32i is?
 one month ago

spandana Group TitleBest ResponseYou've already chosen the best response.0
multipy numerator and denominator with 3+2i
 one month ago

amyna Group TitleBest ResponseYou've already chosen the best response.0
@myininaya yes i multiplied the top and bottom by 3+2i and got 9+6i+6i+4i^2 over 9+6i6i4i^2 and got the final answer as 9+12i / 9 but its the wrong answer
 one month ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
so how did you get 9+4i^2 is 9?
 one month ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
recall i^2 is 1
 one month ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
so you got it right so far to say \[\frac{9+6i+6i+4i^2}{9+6i6i4i^2}\]
 one month ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
and you know again i^2 is 1 so you have \[\frac{9+12i+4(1)}{94(1)}\] wherever there was an i^2 i just replaced it with 1
 one month ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
simplify this and you will see you got the answer as it should be written
 one month ago

amyna Group TitleBest ResponseYou've already chosen the best response.0
Thanks so much @myininaya
 one month ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I think this means you got it so gj
 one month ago
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