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 4 months ago
3+2i / 32i leave answer in a+bi form
the answer is 5/13 + 12/13i , but i keep getting a different answer please help me!!
 4 months ago
3+2i / 32i leave answer in a+bi form the answer is 5/13 + 12/13i , but i keep getting a different answer please help me!!

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myininaya
 4 months ago
Best ResponseYou've already chosen the best response.1so you have 3+2i/32i or do you mean (3+2i)/(32i)?

myininaya
 4 months ago
Best ResponseYou've already chosen the best response.1i think you mean the latter \[\text{ so we have } \frac{3+2i}{32i}\] do you know to put it in a+bi form the first step you must take is to multiply both top and bottom by bottom's conjugate

myininaya
 4 months ago
Best ResponseYou've already chosen the best response.1do you know what the conjugate of 32i is?

spandana
 4 months ago
Best ResponseYou've already chosen the best response.0multipy numerator and denominator with 3+2i

amyna
 4 months ago
Best ResponseYou've already chosen the best response.0@myininaya yes i multiplied the top and bottom by 3+2i and got 9+6i+6i+4i^2 over 9+6i6i4i^2 and got the final answer as 9+12i / 9 but its the wrong answer

myininaya
 4 months ago
Best ResponseYou've already chosen the best response.1so how did you get 9+4i^2 is 9?

myininaya
 4 months ago
Best ResponseYou've already chosen the best response.1so you got it right so far to say \[\frac{9+6i+6i+4i^2}{9+6i6i4i^2}\]

myininaya
 4 months ago
Best ResponseYou've already chosen the best response.1and you know again i^2 is 1 so you have \[\frac{9+12i+4(1)}{94(1)}\] wherever there was an i^2 i just replaced it with 1

myininaya
 4 months ago
Best ResponseYou've already chosen the best response.1simplify this and you will see you got the answer as it should be written

amyna
 4 months ago
Best ResponseYou've already chosen the best response.0Thanks so much @myininaya

myininaya
 4 months ago
Best ResponseYou've already chosen the best response.1I think this means you got it so gj
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