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amyna
 11 months ago
3+2i / 32i leave answer in a+bi form
the answer is 5/13 + 12/13i , but i keep getting a different answer please help me!!
amyna
 11 months ago
3+2i / 32i leave answer in a+bi form the answer is 5/13 + 12/13i , but i keep getting a different answer please help me!!

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myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1so you have 3+2i/32i or do you mean (3+2i)/(32i)?

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1i think you mean the latter \[\text{ so we have } \frac{3+2i}{32i}\] do you know to put it in a+bi form the first step you must take is to multiply both top and bottom by bottom's conjugate

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1do you know what the conjugate of 32i is?

spandana
 11 months ago
Best ResponseYou've already chosen the best response.0multipy numerator and denominator with 3+2i

amyna
 11 months ago
Best ResponseYou've already chosen the best response.0@myininaya yes i multiplied the top and bottom by 3+2i and got 9+6i+6i+4i^2 over 9+6i6i4i^2 and got the final answer as 9+12i / 9 but its the wrong answer

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1so how did you get 9+4i^2 is 9?

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1so you got it right so far to say \[\frac{9+6i+6i+4i^2}{9+6i6i4i^2}\]

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1and you know again i^2 is 1 so you have \[\frac{9+12i+4(1)}{94(1)}\] wherever there was an i^2 i just replaced it with 1

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1simplify this and you will see you got the answer as it should be written

amyna
 11 months ago
Best ResponseYou've already chosen the best response.0Thanks so much @myininaya

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1I think this means you got it so gj
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