anonymous
  • anonymous
lim of x as sin(3x)/(2x) approaches 0
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
agreene
  • agreene
try graphing it.
myininaya
  • myininaya
do you know how to evaluate \[\lim_{u \rightarrow 0}\frac{\sin(u)}{u}?\]
myininaya
  • myininaya
This limit should have been already introduced to you by the squeeze theorem (or at least this is the first way I learned what the above limit is) \[\lim_{u \rightarrow 0}\frac{\sin(u)}{u}=1\] commit this limit to memory it will be useful let's take this limit and see if i can give you a hint on how to do your problem since there is a 3x inside that sin let's let u equal 3x and if u goes to 0 then 3x goes to 0 since u=3x and since 3 doesn't go to 0 then the x must go to 0 so anyways \[\lim_{x \rightarrow 0}\frac{\sin(3x)}{3x}=1 \] try to use this limit here for your problem you may find it necessary to multiply by a 1 to do so

Looking for something else?

Not the answer you are looking for? Search for more explanations.