Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
SanjanaP
Group Title
Help with Increasing and Decreasing Derivatives Please!!
 4 months ago
 4 months ago
SanjanaP Group Title
Help with Increasing and Decreasing Derivatives Please!!
 4 months ago
 4 months ago

This Question is Closed

myininaya Group TitleBest ResponseYou've already chosen the best response.1
what is the question exactly?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
If f'>0, then f is increasing If f'<0, then f is decreasing
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
Oh...sorry I thought I had the attachment on
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
I neeed help with C and D
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
@myininaya
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
so are you having problems with the part highlighted in yellow?
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
Basically...
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
ok then so you know that g' will tell us if g is decreasing or increasing right?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
so find g' given that: \[g(x)=\int\limits_{0}^{x} f(t) dt \] don't look at the picture yet just tell what g' is
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
F(x)+c right?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
no i'm sorry that isn't correct ok let's look at this... I will rewrite it a little... \[g(x)=F(x)F(0)\] where F'=f Now differentiate to find g'
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
I'm sorry..so what is g'?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
you have to differentiate g(x)=F(x)F(0) to find g' can you do that?
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
I'm not sure what differentiate means anymore?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
to find derivative
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
It's f'(x)f'(0)
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
f'(x)(x) right?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I will help you out some more. derivative of g is g' derivative of F is f (this was given above when I said F'=f) derivative of a constant is 0 everything i said in this little post right here will need to be used
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
oh....so the derivative of F(x) is f(x). Is that what you mean?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
That is what I said
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
so do you know F(0) is a constant?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I think you are thinking of f(0) not F(0) f is given not F
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Anyways F(0) is a constant. Because F is a just a function of x any if you plug in a number for x then you will definitely receive a constant  example: Say F(x)=cos(x) well F(0) is definitely a constant because F(0) is 1 and 1 never changes (it is and will always remain 1)
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
So going back to \[g(x)=\int\limits_{0}^{x} f(t) dt \\ g(x)=F(x)F(0)\] can you differentiate g now?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
what that means is you will have to differentiate both sides (not just one side)
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
Can you just tell me where it is increasing and concave up...so I'll try to figure it out?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Try to use what I said earlier... derivative of g is g' derivative of F' is f derivative of a constant is 0 you can do this
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
I would prefer the answer because I have to write the explanation anyway.
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
Okay...so you g(x)= F(x)F(0)
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
that means g'(x) = f(x)0?
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I'm not going to give just the answer. Sorry. But right g'=f so that means the picture given is g'
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
and you know if g'>0, then g is increasing and you know if g'<0, then g is decreasing
 4 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
where on the picture that is given is g' above the x axis (because that is where g is increasing) and when g' is below the xaxis that is where g is decreasing
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
what about concave up?
 4 months ago

SanjanaP Group TitleBest ResponseYou've already chosen the best response.0
dw:1407794546041:dw
 4 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.