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gstprc

  • one year ago

What amount of heat is exchanged when 106.2 grams of substance Y goes from a liquid at 35 degrees Celsius to a solid at the same temperature? Melting point of substance Y = 35 degrees C; ∆Hvaporization = 3.67 J/mol; ∆Hfusion = 3.30 J/mol. MWsubstance y = 28.22 g/mol.

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  1. JoannaBlackwelder
    • one year ago
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    Since we are talking about going from a liquid to a solid at the same temp, we are only freezing the substance.

  2. JoannaBlackwelder
    • one year ago
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    To freeze, we will be removing heat at 3.30 J/mol (the ∆Hfusion). Make sense?

  3. juanpabloJR
    • one year ago
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    What you get?

  4. Tech1
    • one year ago
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    (3.30 J/mol) x (106.2 g / 28.22 g/mol) = 12.4 J

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