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 5 months ago
Who wants a medal?
How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid?
a. 130 gal
c. 13 gal
b. 125 gal
d. None of these
 5 months ago
Who wants a medal? How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid? a. 130 gal c. 13 gal b. 125 gal d. None of these

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JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1I would use the idea of a mass balance of the acid.

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1For example, the amount of acid in the 50 gallons of a 24% acid solution would be 50*.24=12 gallons of acid.

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1Make sense so far?

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1Sweet. Since we don't have the volume of the 60% acid solution, I will call that x.

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1Can you write an expression that shows the volume of acid of the 60% acid solution?

Catseyeglint911
 5 months ago
Best ResponseYou've already chosen the best response.00.5 = 0.6x + (50*0.24) I have a feeling that this isn't right.

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1That is close. The addition side looks good, but what about the volume of the combined solution?

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1@Catseyeglint911?

Catseyeglint911
 5 months ago
Best ResponseYou've already chosen the best response.0sorry I had to step a way for a bit

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1No worries :)

Catseyeglint911
 5 months ago
Best ResponseYou've already chosen the best response.0(0.5*50) = 0.6x + (50*0.24) Is this what you meant?

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1Closer. :) The volume of the 24% solution is 50 gals and the 60% acid solution has volume x gals, so wouldn't the combined 50% acid solution have more volume that 50 gals?

Catseyeglint911
 5 months ago
Best ResponseYou've already chosen the best response.0So we would have to use two variables since we don't know the number of gallons need of the 60% solution nor do we know the number of gallons of the final solution?

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1We could, but we don't have to. Since we know we are adding two volumes together and one volume is 50 gallons and we defined the second volume to be x gallons. So the combined volume is 50+x gallons.

Catseyeglint911
 5 months ago
Best ResponseYou've already chosen the best response.0(x+50) = 0.6 + (50*0.24) It's still wrong isn't it?

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1Last time you put (0.5*50) = 0.6x + (50*0.24) which was closer. The only thing you needed to change was (0.5*[50+x]) = 0.6x + (50*0.24)

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1The 50 to a 50+x

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1Do you follow me?

Catseyeglint911
 5 months ago
Best ResponseYou've already chosen the best response.0Ooohhh! I see now. :D

JoannaBlackwelder
 5 months ago
Best ResponseYou've already chosen the best response.1Can you solve for x?

Catseyeglint911
 5 months ago
Best ResponseYou've already chosen the best response.0(0.5*[50+x]) = 0.6x + (50*0.24) 25 + 0.5x = 0.6x + 12 13 + 0.5x = 0.6x 13 = 0.1x 130 = x right?

Catseyeglint911
 5 months ago
Best ResponseYou've already chosen the best response.0Thank you so much. :)
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