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anonymous
 one year ago
Who wants a medal?
How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid?
a. 130 gal
c. 13 gal
b. 125 gal
d. None of these
anonymous
 one year ago
Who wants a medal? How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid? a. 130 gal c. 13 gal b. 125 gal d. None of these

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JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1I would use the idea of a mass balance of the acid.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1For example, the amount of acid in the 50 gallons of a 24% acid solution would be 50*.24=12 gallons of acid.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Make sense so far?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Sweet. Since we don't have the volume of the 60% acid solution, I will call that x.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Can you write an expression that shows the volume of acid of the 60% acid solution?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.00.5 = 0.6x + (50*0.24) I have a feeling that this isn't right.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1That is close. The addition side looks good, but what about the volume of the combined solution?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1@Catseyeglint911?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry I had to step a way for a bit

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1No worries :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(0.5*50) = 0.6x + (50*0.24) Is this what you meant?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Closer. :) The volume of the 24% solution is 50 gals and the 60% acid solution has volume x gals, so wouldn't the combined 50% acid solution have more volume that 50 gals?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So we would have to use two variables since we don't know the number of gallons need of the 60% solution nor do we know the number of gallons of the final solution?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1We could, but we don't have to. Since we know we are adding two volumes together and one volume is 50 gallons and we defined the second volume to be x gallons. So the combined volume is 50+x gallons.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(x+50) = 0.6 + (50*0.24) It's still wrong isn't it?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Last time you put (0.5*50) = 0.6x + (50*0.24) which was closer. The only thing you needed to change was (0.5*[50+x]) = 0.6x + (50*0.24)

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1The 50 to a 50+x

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Do you follow me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ooohhh! I see now. :D

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.1Can you solve for x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(0.5*[50+x]) = 0.6x + (50*0.24) 25 + 0.5x = 0.6x + 12 13 + 0.5x = 0.6x 13 = 0.1x 130 = x right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much. :)
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