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I would use the idea of a mass balance of the acid.

Make sense so far?

yes

Sweet. Since we don't have the volume of the 60% acid solution, I will call that x.

Can you write an expression that shows the volume of acid of the 60% acid solution?

0.5 = 0.6x + (50*0.24)
I have a feeling that this isn't right.

That is close. The addition side looks good, but what about the volume of the combined solution?

sorry I had to step a way for a bit

No worries :)

(0.5*50) = 0.6x + (50*0.24)
Is this what you meant?

(x+50) = 0.6 + (50*0.24)
It's still wrong isn't it?

The 50 to a 50+x

Do you follow me?

Ooohhh! I see now. :D

Can you solve for x?

(0.5*[50+x]) = 0.6x + (50*0.24)
25 + 0.5x = 0.6x + 12
13 + 0.5x = 0.6x
13 = 0.1x
130 = x
right?

Awesome! :)

Thank you so much. :)

No worries