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anonymous
 2 years ago
Who wants a medal?
How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid?
a. 130 gal
c. 13 gal
b. 125 gal
d. None of these
anonymous
 2 years ago
Who wants a medal? How much of a 60% acid solution must be mixed with 50 gallons of a 24% acid solution to obtain a solution that is 50% acid? a. 130 gal c. 13 gal b. 125 gal d. None of these

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JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1I would use the idea of a mass balance of the acid.

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1For example, the amount of acid in the 50 gallons of a 24% acid solution would be 50*.24=12 gallons of acid.

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1Make sense so far?

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1Sweet. Since we don't have the volume of the 60% acid solution, I will call that x.

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1Can you write an expression that shows the volume of acid of the 60% acid solution?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.00.5 = 0.6x + (50*0.24) I have a feeling that this isn't right.

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1That is close. The addition side looks good, but what about the volume of the combined solution?

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1@Catseyeglint911?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0sorry I had to step a way for a bit

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1No worries :)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0(0.5*50) = 0.6x + (50*0.24) Is this what you meant?

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1Closer. :) The volume of the 24% solution is 50 gals and the 60% acid solution has volume x gals, so wouldn't the combined 50% acid solution have more volume that 50 gals?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So we would have to use two variables since we don't know the number of gallons need of the 60% solution nor do we know the number of gallons of the final solution?

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1We could, but we don't have to. Since we know we are adding two volumes together and one volume is 50 gallons and we defined the second volume to be x gallons. So the combined volume is 50+x gallons.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0(x+50) = 0.6 + (50*0.24) It's still wrong isn't it?

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1Last time you put (0.5*50) = 0.6x + (50*0.24) which was closer. The only thing you needed to change was (0.5*[50+x]) = 0.6x + (50*0.24)

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1The 50 to a 50+x

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1Do you follow me?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Ooohhh! I see now. :D

JoannaBlackwelder
 2 years ago
Best ResponseYou've already chosen the best response.1Can you solve for x?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0(0.5*[50+x]) = 0.6x + (50*0.24) 25 + 0.5x = 0.6x + 12 13 + 0.5x = 0.6x 13 = 0.1x 130 = x right?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you so much. :)
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