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math92130
Group Title
2 Al(NO3)3 + 3 Na2CO3 = Al2(CO3)3(s) + 6 NaNO3
Use the limiting reagent to determine how many grams of Al2(CO3)3 should precipitate out in the reaction. (2 points)
 one month ago
 one month ago
math92130 Group Title
2 Al(NO3)3 + 3 Na2CO3 = Al2(CO3)3(s) + 6 NaNO3 Use the limiting reagent to determine how many grams of Al2(CO3)3 should precipitate out in the reaction. (2 points)
 one month ago
 one month ago

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math92130 Group TitleBest ResponseYou've already chosen the best response.0
so i figured out theat the limiting reagent is Al(NO3)3 since there are 4.667 moles of al(no3)3 and 6 moles of na2co3 needed
 one month ago

math92130 Group TitleBest ResponseYou've already chosen the best response.0
@JoannaBlackwelder
 one month ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
Cool. Now use the amount of the limiting reactant to calculate the mass of the precipitate using stoichiometry.
 one month ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
The precipitate is the solid.
 one month ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
Because, if you're not part of the solution, you're part of the precipitate!! Hahahaha!
 one month ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
:D
 one month ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
I've gotta go now though. I'll be back on later. Have fun!!!
 one month ago
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