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math92130
Group Title
2 Al(NO3)3 + 3 Na2CO3 = Al2(CO3)3(s) + 6 NaNO3
Use the limiting reagent to determine how many grams of Al2(CO3)3 should precipitate out in the reaction. (2 points)
 3 months ago
 3 months ago
math92130 Group Title
2 Al(NO3)3 + 3 Na2CO3 = Al2(CO3)3(s) + 6 NaNO3 Use the limiting reagent to determine how many grams of Al2(CO3)3 should precipitate out in the reaction. (2 points)
 3 months ago
 3 months ago

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math92130 Group TitleBest ResponseYou've already chosen the best response.0
so i figured out theat the limiting reagent is Al(NO3)3 since there are 4.667 moles of al(no3)3 and 6 moles of na2co3 needed
 3 months ago

math92130 Group TitleBest ResponseYou've already chosen the best response.0
@JoannaBlackwelder
 3 months ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
Cool. Now use the amount of the limiting reactant to calculate the mass of the precipitate using stoichiometry.
 3 months ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
The precipitate is the solid.
 3 months ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
Because, if you're not part of the solution, you're part of the precipitate!! Hahahaha!
 3 months ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
:D
 3 months ago

JoannaBlackwelder Group TitleBest ResponseYou've already chosen the best response.0
I've gotta go now though. I'll be back on later. Have fun!!!
 3 months ago
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