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nirmalnema

  • 2 years ago

plz help..!!

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  1. nirmalnema
    • 2 years ago
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    \[(x+1/x =11 ) then find ( x^2+1/x^2)\]

  2. nirmalnema
    • 2 years ago
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    @chmvijay

  3. anonymous
    • 2 years ago
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    Whatchu mean?

  4. anonymous
    • 2 years ago
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    X+1 divided by x=11???

  5. nirmalnema
    • 2 years ago
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    x+ (1/x) mentioned in the que..!!

  6. anonymous
    • 2 years ago
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    Can you take out the X?

  7. anonymous
    • 2 years ago
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    it's X+(1/X)=11 So, In the equation can't you take out the X as common factor?

  8. nirmalnema
    • 2 years ago
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    @nincompoop

  9. nirmalnema
    • 2 years ago
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    @Luigi0210

  10. anonymous
    • 2 years ago
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    idk...

  11. nirmalnema
    • 2 years ago
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    its ok no problem..thanks for trying..

  12. Luigi0210
    • 2 years ago
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    I think you need to solve for x in the first one, then once you find that you plug that value into the second..

  13. nirmalnema
    • 2 years ago
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    yaa but how.

  14. anonymous
    • 2 years ago
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    yea.. that's what I was trying to do but that X+(1/X)=11 is weird

  15. anonymous
    • 2 years ago
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    It's the same variable so I tried to factor it out but I don't think that's how it works...

  16. Luigi0210
    • 2 years ago
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    Multiply both sides by x, since it's an equation I think you can do that..

  17. Luigi0210
    • 2 years ago
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    It'll be \(\Large x^2+1=11x\)

  18. Luigi0210
    • 2 years ago
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    Nvm seems complicated xD

  19. anonymous
    • 2 years ago
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    Why multiply both sides, it'll make X^2 ... that will be one dirty sitaution

  20. anonymous
    • 2 years ago
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    the question is not clear to me

  21. nirmalnema
    • 2 years ago
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    its same as done by @DanielK16 but x is so weird

  22. Luigi0210
    • 2 years ago
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    @myininaya can help us ~

  23. anonymous
    • 2 years ago
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    I tried some equation calculators on the internet and they come out like quadratics with two answers...

  24. myininaya
    • 2 years ago
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    i'm confused is it (x+1)/x=11 or x+1/x=11?

  25. anonymous
    • 2 years ago
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    second one the 1/x is a fraction

  26. nirmalnema
    • 2 years ago
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  27. anonymous
    • 2 years ago
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    Is this calculus? with derivatives>?

  28. myininaya
    • 2 years ago
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    so we have this: \[x+\frac{1}{x}=11 ; x^2+\frac{1}{x^2}\]

  29. nirmalnema
    • 2 years ago
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    @aayushi.somani

  30. anonymous
    • 2 years ago
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    correct @ myininaya

  31. myininaya
    • 2 years ago
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    my initial move is to square both sides of that equation first

  32. myininaya
    • 2 years ago
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    oh yes that will work perfectly and beautifully

  33. myininaya
    • 2 years ago
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    square both of sides of the equation x+1/x=11 to see magic

  34. myininaya
    • 2 years ago
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    This is only a 2-step problem.

  35. anonymous
    • 2 years ago
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    Woah~~

  36. anonymous
    • 2 years ago
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    I saw magic

  37. myininaya
    • 2 years ago
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    lol

  38. myininaya
    • 2 years ago
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    @nirmalnema do you see?

  39. nirmalnema
    • 2 years ago
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    nops..!

  40. myininaya
    • 2 years ago
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    do you know how to square (x+1/x)?

  41. myininaya
    • 2 years ago
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    \[(x+1/x)^2 =? \]

  42. nirmalnema
    • 2 years ago
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    yaa.

  43. myininaya
    • 2 years ago
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    Remember this means \[(x+\frac{1}{x})(x+\frac{1}{x})\] now multiply

  44. nirmalnema
    • 2 years ago
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    ohh thanks i got it..its 119

  45. myininaya
    • 2 years ago
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    yep

  46. myininaya
    • 2 years ago
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    I thought to square both sides because the equation involved no items without squares and what we wanted to find involved those items with squares

  47. nirmalnema
    • 2 years ago
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    ok..!!

  48. myininaya
    • 2 years ago
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    oops double negative i hope you know what i mean

  49. myininaya
    • 2 years ago
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    involved items without squares*

  50. nirmalnema
    • 2 years ago
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    yaa ....

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