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\[(x+1/x =11 ) then find ( x^2+1/x^2)\]

Whatchu mean?

X+1 divided by x=11???

x+ (1/x) mentioned in the que..!!

Can you take out the X?

it's X+(1/X)=11
So, In the equation can't you take out the X as common factor?

idk...

its ok no problem..thanks for trying..

yaa but how.

yea.. that's what I was trying to do but that X+(1/X)=11 is weird

It's the same variable so I tried to factor it out but I don't think that's how it works...

Multiply both sides by x, since it's an equation I think you can do that..

It'll be \(\Large x^2+1=11x\)

Nvm seems complicated xD

Why multiply both sides, it'll make X^2 ... that will be one dirty sitaution

the question is not clear to me

its same as done by @DanielK16 but x is so weird

@myininaya can help us ~

i'm confused
is it (x+1)/x=11
or x+1/x=11?

second one the 1/x is a fraction

Is this calculus? with derivatives>?

so we have this:
\[x+\frac{1}{x}=11 ; x^2+\frac{1}{x^2}\]

@aayushi.somani

correct @ myininaya

my initial move is to square both sides of that equation first

oh yes that will work perfectly and beautifully

square both of sides of the equation x+1/x=11
to see magic

This is only a 2-step problem.

Woah~~

I saw magic

lol

@nirmalnema do you see?

nops..!

do you know how to square (x+1/x)?

\[(x+1/x)^2 =? \]

yaa.

Remember this means
\[(x+\frac{1}{x})(x+\frac{1}{x})\]
now multiply

ohh thanks i got it..its 119

yep

ok..!!

oops double negative
i hope you know what i mean

involved items without squares*

yaa ....